Answer: I belive that the Answer is C.) Conduction
Explanation:
Answer:
The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground
Explanation:
given information:
h =9.8
t =1 s
g = 9.8
the average speed
v = 1/2 gt²
= 1/2 (9.8) (1)²
= 4.8 m/s
the distance in 1s
h = v t
= 4.8 (1)
= 4.8 m
the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground
=
Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants (
= 0) zero, so let's use the equation
y =
t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
It slows the object down so it cannot move well and evetually the object cannot be pushed and farther
Answer: They have different rigidities.
Explanation: