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wel
3 years ago
7

What type of energy is it when rain falls?

Physics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

The falling raindrop is converting gravitational PE into KE and thermal energy through resistance. The PE is from solar energy evaporating the liquid water to vapor and powering the weather that formed the cloud.

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In your everyday life you come across a range of motions in which
nydimaria [60]
Acceleration is in the direction of motion 
7 0
3 years ago
North America experienced all of the following during the last glacial period EXCEPT alpine glaciers covered the Rocky and Casca
Juli2301 [7.4K]

Answer:

the Hudson Bay was covered with alpine glaciers

Explanation:

During the last glacial period, large portions of North America were covered with ice. The majority of the ice was from the ice sheets that were covering Canada and the northern part of the United States, and the alpine glaciers on the mountain ranges. Hudson Bay was all frozen at this point of time. It was not covered with alpine glaciers though, instead it was covered with the ice of the extended ice sheets, with the ice cover reaching up to 2 km in thickness.

5 0
3 years ago
Physics!!! please help D:
Ugo [173]
Answer: A

Explanation: isotopes of the same thing element have the same number of protons in the nucleus but differ in the number of neutrons.
6 0
2 years ago
A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the
BartSMP [9]

Answer:

r=1.14m

Explanation:

\theta is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

F_m=F_c\\qvB=F_c(1)

F_c is the centripetal force and is defined as:

F_c=m\frac{v^2}{r}

Here v is the proton's speed and r is the radius of the circular motion. Replacing this in (1) and solving for r:

qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}

Recall that 1 J is equal to 6.242*10^{12}MeV, so:

4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J

We can calculate v from the kinetic energy of the proton:

K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}

Finally, we calculate the radius of the proton path:

r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m

8 0
3 years ago
if the current is 0.4 A for the 20 ohm resistor, what is the value for the potential difference? ii) Would it be different for t
Genrish500 [490]

Answer:potential difference is more or less like voltage. Using ohms, V=IR

Where V is Voltage

I is Current =0.4A

R is Resistance=20ohms

V=0.4*20

V=8V

Hence the potential difference will be 8V.

ii) V=0.4*30

V=12V

Explanation:

The voltage of potential difference is directly proportional to the current and the resistance. So if one increase or decrease, it will have impact on the other.

From the calculations, when the resistance increase, the voltage will increase to appreciate the change.

8 0
3 years ago
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