Answer:
Q1 --> 17
Q2 --> 20
Q3 --> 22.5
Interquartile
Range IQR 5.5
Step-by-step explanation:
Step 1
We rearrange the given data set
10, 16, 18, 20, 20, 21, 24, 25
Q2 (median):
Q1:
Q3:
Interquartile Range (IQR): Q3-Q1 -
Answer:
a) ![N= (5C1) *(5C1) *(5C1) = 5*5*5 = 125](https://tex.z-dn.net/?f=%20N%3D%20%285C1%29%20%2A%285C1%29%20%2A%285C1%29%20%3D%205%2A5%2A5%20%3D%20125)
b) ![N = (5C1)*(4C1) *(3C1) = 5*4*3 = 60](https://tex.z-dn.net/?f=%20N%20%3D%20%285C1%29%2A%284C1%29%20%2A%283C1%29%20%3D%205%2A4%2A3%20%3D%2060)
Step-by-step explanation:
For this case our sample space is the 5 letters given:
![S= [F,G, H, I, J]](https://tex.z-dn.net/?f=%20S%3D%20%5BF%2CG%2C%20H%2C%20I%2C%20J%5D)
And we want to find the number of three letter words can be made from the sample space with some conditions
Part a
For this case the repetition is allowed so then each time we will have 5 possibilites in order to select one letter so if we use combinatories we have:
![N= (5C1) *(5C1) *(5C1) = 5*5*5 = 125](https://tex.z-dn.net/?f=%20N%3D%20%285C1%29%20%2A%285C1%29%20%2A%285C1%29%20%3D%205%2A5%2A5%20%3D%20125)
So then we will have 125 possible combinations of 3 words letters with the 5 provided
We need to remember that ![nC x = \frac{n!}{(n-x)! x!}](https://tex.z-dn.net/?f=%20nC%20x%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-x%29%21%20x%21%7D)
Part b
For this case the repetition is not allowed so then the possible number of possibilities are:
![N = (5C1)*(4C1) *(3C1) = 5*4*3 = 60](https://tex.z-dn.net/?f=%20N%20%3D%20%285C1%29%2A%284C1%29%20%2A%283C1%29%20%3D%205%2A4%2A3%20%3D%2060)
So then we will have 60 possible combinations of 3 words letters with the 5 provided
Answer:
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Answer:
18°
Step-by-step explanation:
1. ∠A and ∠B are complementary angles, so they add up to 90°.
- This means that 2x - 4 + 5x + 17 = 90
2. To find the measure of ∠A, we first have to solve for x.
3. (Solving)
Step 1: Simplify both sides of the equation.
Step 2: Subtract 13 from both sides.
Step 3: Divide both sides by 7.
4. Now that we know x = 11, let's plug that value into (2x - 4) to find the measure of Angle A.
Therefore, the measure of ∠A = 18°.