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1 answer:
Answer:
The resulting force on the first object is 800 N.
Explanation:
Given;
force exerted on one of the objects, F₁ = 400 N
let the first charge = q₁
let the second charge = q₂
The force of repulsion between the objects is calculated using Coulomb's law;
Therefore, the resulting force on the first object is 800 N.
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Explanation:
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Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is . As the capacitance of capacitor is given as follows.
C =
It is known that the dielectric strength of air is as follows.
E =
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
=
=
=
=
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.