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2 years ago

Please helppppppp!!!!!!

Physics

1 answer:

Mamont248 [21]2 years ago

6 0

Answer:

The resulting force on the first object is 800 N.

Explanation:

Given;

force exerted on one of the objects, F₁ = 400 N

let the first charge = q₁

let the second charge = q₂

The force of repulsion between the objects is calculated using Coulomb's law;

$F =\frac{kq_1q_2}{r^2} \\\\\frac{k}{r^2} = \frac{F}{q_1q_2} = \frac{F_1}{q_1\times2q_2} \\\\F_1 = \frac{F(q_1\times2q_2)}{q_1q_2} \\\\F_1 = 2F\\\\F_1 = 2(400 \ N)\\\\F_1 = 800 \ N$

Therefore, the resulting force on the first object is 800 N.

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2 years ago

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Answer:

Explanation:

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3 years ago

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Part A:
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Substituting,
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ANSWER: 3 m/s²

Part B:
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F = m x a
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Substituting,
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