Answer:
A system of linear equations will have exactly one point of intersection, for example:
2x+y=5
-x+y=2
However, a system of linear equations with no solution will have no points of intersection, for example:
-4x+10y=6
2x-5y=3
Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe
And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)
I attached a photo below, and one of how to graph it
The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
<h3>Vertex Form of a quadratic expression</h3>
Given the quadratic expressions
1.5x^2+6x+......
1.5(x^2 + 4x)
Using the completing the square method
The coefficient of x = 4
Half of the coefficient = 4/2 = 2
The square of the result = 2^2 = 4
The equation is expressed as:
f(x) = 1.5(x^2+4x+ 4) - 4
f(x) = 1.5(x+2)^2 - 4
Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
Learn more on completing the square method here: brainly.com/question/1596209
The answer is 45 :^))))))))))