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3 years ago

Describe the trends in electron configuration in the periodic table by selecting the terms from the drop-down menus.

Chemistry

2 answers:

sladkih [1.3K]3 years ago

7 0

The number of valence electrons increases from the left to right across a period.
The number of valence electrons stays the same from the top to the bottom of a group.
Electrons are added into the outermost s orbital in Groups 1 and 2.
Electrons are added into the outermost d orbital in Groups 3 through 12.
Electrons are added into the outermost p orbital in Groups 13 through 18.

natka813 [3]3 years ago

5 0

1)Left to right in a period it goes up by one
2) the number valence electrons are the same from top to bottom

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Pls just help me out the vid is 6 Chemical Reactions That Changed History; need help on no.6. I DON’T EVEN KNOW HOW TO SOLVE IT

GREYUIT [131]

Explanation:

HCL you can do it yourself .try again

4 0

3 years ago

Develop a demonstration to show how weight is not the same thing as mass

maksim [4K]

Answer with Explanation:

"Mass" and "weight" should never be used interchangeably with each other. Mass refers to the total amount of matter that can be measured in an object, while weight refers to the measure of the force of gravity that is acting on the object's mass.

The mass of an object is constant (meaning, it doesn't change even if the object will be placed on another location) while the weight of an object relies on the force of gravity. So, this means that your mass on Earth and on the moon are identical, however, your weight on Earth and on the Moon are different. You will weigh lesser on the Moon because it has a lesser surface gravity than that of Earth.

So, this explains the answer.

4 0

3 years ago

Given that 25.0 mL of mercury has a mass of 340.0 g, calculate (a) the density of mercury and (b) the mass of 120.0 mL of mercur

natita [175]

Answer :

(a) The density of mercury is, 13.6 g/ml

(b) The mass of 120.0 ml of mercury is, 1632 grams

Explanation :

(a) Now we have to calculate the density of mercury.

Given :

Volume of mercury = 25.0 ml

Mass of mercury = 340.0 g

Formula used :

$\text{Density of mercury}=\frac{\text{Mass of mercury}}{\text{Volume of mercury}}$

$\text{Density of mercury}=\frac{340.0g}{25.0ml}=13.6g/ml$

Therefore, the density of mercury is, 13.6 g/ml

(b) Now we have to calculate the mass of 120.0 ml of mercury.

As, 25.0 ml of mercury has mass = 340.0 g

So, 120.0 ml of mercury has mass = $\frac{120.0ml}{25.0ml}\times 340.0g=1632g$

Therefore, the mass of 120.0 ml of mercury is, 1632 grams

3 0

3 years ago

How did Bohr describe the arrangement of particles within an atom?

alexandr1967 [171]

Answer: A

Explanation: Protons and neutrons form the nucleus of the atom, with electrons orbiting it.

4 0

3 years ago

Read 2 more answers

stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,

Law Incorporation [45]

Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

8 0

3 years ago