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AURORKA [14]
3 years ago
5

Describe the trends in electron configuration in the periodic table by selecting the terms from the drop-down menus.

Chemistry
2 answers:
sladkih [1.3K]3 years ago
7 0
  1. The number of valence electrons increases from the left to right across a period.
  2. The number of valence electrons stays the same from the top to the bottom of a group.
  3. Electrons are added into the outermost s orbital in Groups 1 and 2.
  4. Electrons are added into the outermost d orbital in Groups 3 through 12.
  5. Electrons are added into the outermost p orbital in Groups 13 through 18.
natka813 [3]3 years ago
5 0
1)Left to right in a period it goes up by one
2) the number valence electrons are the same from top to bottom
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PLEASE HELP!
pogonyaev

Answer:

Q = 2.60 • 10^{3} J

Explanation:

Our specific heat capacity equation is:

Q = mC∆T

Q is the energy in joules.

m is the mass of the substance.

∆T is the temperature chance.

Let's plug in what we know.

  • We have 76.0 g of octane
  • The specific heat capacity of octane is 2.22 J/(g•K)
  • The temperature increases from 10.6º to 26.0º (a 15.4º increase)

Q = 76.0(2.22)(15.4)

Multiply.

Q = 2598.288

We want three significant figures.

Q = 2.60 • 10^{3}

or

Q = 2590 J

Hope this helps!

3 0
3 years ago
Read 2 more answers
Which statement is true about elements in a period on the periodic table?
frozen [14]

Answer:

they have differnet properties that repeat across the next period

Explanation:

5 0
3 years ago
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Click the button that shows the correct relationship of the electron affinities of the elements sodium and phosphorus.
VikaD [51]

Answer:

The second option

Explanation:

I took the quiz and got it correct

3 0
3 years ago
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In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.
mihalych1998 [28]

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

8 0
3 years ago
What are the complete Ionic and Net Ionic equations for the following
zhenek [66]

Answer:

Check photo

Explanation:

5 0
3 years ago
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