The ingredients that is important in making plastics is natural gas plant liquids.
Natural gas liquids (NGLs) are components of natural gas which are separated from the gas state in the form of liquids. They many applications including; plastic production, inputs for petrochemical plants, they are also burned for space heat and cooking, and can also be blended into vehicle fuel.
In the manufacturing of plastics, come components of NGLs are used. And for this case, ethane. Ethane is used in the production of ethylene which are passed through pressure and catalyst to be turned to plastics like polythene.
The reason why they are mostly used in the manufacturing plastics than other resources like crude oil is that it is much cleaner.
Learn more about natural gas liquids here:
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Answer : The correct expression for equilibrium constant will be:
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Therefore, the correct expression for equilibrium constant will be, ![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Explanation:
The given precipitation reaction will be as follows.

Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity = 
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity = 
0.269 M = 
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles = 
0.307 mol = 
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.
Answer:
A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.
<u>The pressure for oxygen is 3 kPa</u>
Explanation:
According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

So,
For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:




Insert the values in :


