Answer:
43.75 miles must a person walk to utilize the energy in (“burn”) a pound of fat.
Explanation:
3,500 calories are present in 1 pound of the fat.
Thus, given that:
<u>4 calories are burnt in 1 minute of walking.</u>
So,
1 calories are burnt in 1/4 minute of walking.
Or,
<u>1 calories are burnt in 0.25 minute of walking.</u>
Thus,
<u>3500 calories are burnt in 0.25*3500 minutes of walking</u>
Minutes of walking needed to burn 3500 calories = 875 minutes.
Also, given that:
<u>20 minutes of walking covers 1 mile.</u>
<u>1 minute of walking covers 1/20 mile.</u>
So,
<u>875 minutes of walking covers (1/20)*875 mile.</u>
<u>43.75 miles must a person walk to utilize the energy in (“burn”) a pound of fat.</u>
Answer:
The velocity of the proton is 
Explanation:
The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:
p=m*v Equation (1)
Where:
p: Is the momentum in kg*m/s
m: Is mass of the particle in kg
v: Is the velocity of the particle in m/s
Data known:
m= 1,6726 × 10^–27 kg : mass of the proton
p= 4.96 X 10^-19 kg.m/s.
We replace this data in the Equation (1):




Answer: The velocity of the proton is 
Answer:
(A)
Explanation:
P1 = MVcos 30
P2 = MVcos 30
️P = -2 mvcos 30
️P = - square root of 3 mv
f1 = 2mv/ ️t
force on the wall = 2
f2 = square root of 3mv/ ️t, so f1 > f2
Answer:
685.6 J
Explanation:
The latent heat of vaporization of ammonia is
L = 1371.2 kJ/kg
mass of ammonia, m = 0.0005 Kg
Heat = mass x latent heat of vaporization
H = 0.0005 x 1371.2
H = 0.686 kJ
H = 685.6 J
Thus, the amount of heat required to vaporize the ammonia is 685.6 J.
Answer:
2 min 40 s.
Explanation:
Distance = 800 ft
Speed (walking speed) = 300 ft/min
Speed = distance/time
Time, t = 800/300
= 8/3
= 2 min 40 s.