As per given condition of point B we can see that height at point B is "h/2" from the ground
So we know that potential energy is given as
U = mgh
so here we have to put height h = h/2
so potential energy is U = mgh/2
now for kinetic energy we need to find the speed of it after falling the distance h/2
now by kinematics we will have
now for kinetic energy
now total energy will be given as
now for point C we can say that it is the point near to ground
So here height is ZERO
now potential energy will also be zero
U = 0
now for kinetic energy we need to find speed
now kinetic energy
now again we have total energy