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guajiro [1.7K]
3 years ago
6

A student wants to approximate the amount of work that the force due to gravity does on the student as the student walks up a se

t of stairs. Which of the following measurements must the student collect in order to approximate the amount of work done by Earth on the student?
a. The mass of the student.
b. The angle between the inclined portion of the stairs and the horizontal.
c. The total inclined length of the stairs.
d. The final vertical height above the initial vertical position.
Physics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

Options A and D

Explanation:

In this question the student needs to collect these measurements in order to approximate the work done

A. The mass of the student

D. The final vertical height above the initial vertical position.

Workdone = mgh

m = mass

g = gravity = 9.8m/s²

h = vertical height between the initial and the final positions.

The vertical height has to be known as gravity only acts straight down.

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A dolphin can swim at a constant speed of 12.5 m/s. How
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Answer:

\boxed {\tt 3.6 \ seconds}

Explanation:

Time can be found by dividing the distance by the speed.

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d= 45 \ m \\s= 12.5 \ m/s

t=\frac{45 \ m}{12.5 \ m/s}

Divide. Note that the meters, or "m" will cancel each other out.

t=\frac{45 }{12.5 \ s}

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3 years ago
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Determine the amount of potential energy of a 5N book that is 1.5m high on a shelf.
Alex73 [517]

Answer:

Potential energy of book = 7.5 J

Explanation:

Given:

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Potential energy of book = Mass x Acceleration of gravity x Height

We know that;

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So,

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Dovator [93]
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
3 years ago
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