-0 m/s 
- average velocity=displacement/time 
- the runners displacement is zero so her average velocity must be zero
        
             
        
        
        
Answer: _____= beautiful, yet annoying frustrating death
Explanation:
 
        
                    
             
        
        
        
Answer:
995.12 N/C
Explanation:
R = 9 cm = 0.09 m 
σ = 9 nC/m^2 = 9 x 10^-9 C/m^2
r = 9.1 cm = 0.091 m
q = σ x 4π R² = 9 x 10^-9 x 4 x 3.14 x 0.09 x 0.09 = 9.156 x 10^-10 C
E = kq / r^2 
E = ( 9 x 10^9 x 9.156 x 10^-10) / (0.091 x 0.091) 
E = 995.12 N/C
 
        
             
        
        
        
 The velocity of the ball when it was caught is 12.52 m/s.
<em>"Your question is not complete it seems to be missing the following, information"</em>,
find the velocity of the ball when it was caught.
The given parameters;
maximum height above the ground reached by the ball, H = 38 m
height above the ground where the ball was caught, h = 30 m
The height traveled by the ball when it was caught is calculated as follows;
y = H - h
y = 38 - 30 = 8 m
The velocity of the ball when it was caught is calculated as;

Thus, the velocity of the ball when it was caught is 12.52 m/s.
Learn more here: brainly.com/question/14582703
 
        
             
        
        
        
Answer:
•2 kilometres.................