Answer: <em>1, i think :)</em>
Answer:
The area of the octagon is <u>505.76 </u>![inches^{2}](https://tex.z-dn.net/?f=inches%5E%7B2%7D)
Step-by-step explanation:
In this question, we are tasked with calculating the area of an octagon given the values of the apothem and the perimeter
Mathematically, the area can be calculated using the formula below;
Area = 1/2 × apothem × perimeter
where according to the question, the apothem = 11.6 inches and the perimeter = 87.2 inches
Plugging these value into the equation given above, we have
Area = 1/2 × 11.6 × 87.2 = 505.76 ![inches^{2}](https://tex.z-dn.net/?f=inches%5E%7B2%7D)
Answer:
The correct answer is 6000
Step-by-step explanation:
I disagree because 10 to the 3rd power = 1000 x 6 = 6000
The mistake he made was that George multiplied all of the number so, 6 x 10 x 3 = 60 x 3 = 180.
The area of the shaded portion inside the given triangle is; 1254 square meters
<h3>How to find the area of shaded portion?</h3>
Looking at the given image, we can say that;
Area of Shaded Portion = Area of Triangle - Area of Circle
Area of Triangle = ¹/₂ * 56 * 56
Area of Triangle = 1568 m²
Area of Circle = πr²
Area of Circle = π * (20/2)²
Area of Circle = 314 m²
Thus;
Area of Shaded Portion = 1568 m² - 314 m²
Area of Shaded Portion = 1254 square meters
Read more about Area of Shaded Portion at; brainly.com/question/10090807
#SPJ1
Answer: ![\vec{v}=1(17)\hat{i}+2(7)\hat{j}+3(6.67)\hat{k}](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D%3D1%2817%29%5Chat%7Bi%7D%2B2%287%29%5Chat%7Bj%7D%2B3%286.67%29%5Chat%7Bk%7D)
Step-by-step explanation:
Since we have given that
![\vec{u}=5\hat{i}-4\hat{j}+2\hat{k}\\\\and\\\\\vec{w}=}](https://tex.z-dn.net/?f=%5Cvec%7Bu%7D%3D5%5Chat%7Bi%7D-4%5Chat%7Bj%7D%2B2%5Chat%7Bk%7D%5C%5C%5C%5Cand%5C%5C%5C%5C%5Cvec%7Bw%7D%3D%7D)
We need to find the value of
in the form of ![\vec{v}=1\hat{i}+2\hat{j}+3\hat{k}](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D%3D1%5Chat%7Bi%7D%2B2%5Chat%7Bj%7D%2B3%5Chat%7Bk%7D)
so, it becomes,
![5(5\hat{i}-4\hat{j}+2\hat{k})+2(-4\hat{i}+3\hat{j}+5\hat{k})\\\\=25\hat{i}-20\hat{j}+10\hat{k}-8\hat{i}+6\hat{j}+10\hat{k}\\\\=17\hat{i}-14\hat{j}+20\hat{k}](https://tex.z-dn.net/?f=5%285%5Chat%7Bi%7D-4%5Chat%7Bj%7D%2B2%5Chat%7Bk%7D%29%2B2%28-4%5Chat%7Bi%7D%2B3%5Chat%7Bj%7D%2B5%5Chat%7Bk%7D%29%5C%5C%5C%5C%3D25%5Chat%7Bi%7D-20%5Chat%7Bj%7D%2B10%5Chat%7Bk%7D-8%5Chat%7Bi%7D%2B6%5Chat%7Bj%7D%2B10%5Chat%7Bk%7D%5C%5C%5C%5C%3D17%5Chat%7Bi%7D-14%5Chat%7Bj%7D%2B20%5Chat%7Bk%7D)
So, in the form of ![\vec{v}](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D)
So, it becomes,
![\vec{v}=1(17)\hat{i}+2(7)\hat{j}+3(6.67)\hat{k}](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D%3D1%2817%29%5Chat%7Bi%7D%2B2%287%29%5Chat%7Bj%7D%2B3%286.67%29%5Chat%7Bk%7D)