All categories

3 years ago

100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.

Chemistry

1 answer:

yawa3891 [41]3 years ago

7 0

Volume of H₂O added = 175 ml

<h3>Further explanation</h3>

Given

100 gm of a 55% (M/M) and 20% (M/M) nitric acid solution

Required

waters added

Solution

starting solution

mass H₂O = 45%=45 g

%mass of H₂O in new solution = 100%-20%=80%

Can be formulated for %mass H₂O :

$\tt \dfrac{45+x}{100+x}=80\%\\\\45+x=0.8(100+x)\\\\45+x=80+0.8x\\\\35=0.2x\rightarrow x=175~g$

For water mass=volume(density = 1 g/ml)

So volume added = 175 ml

You might be interested in

What mass of S8 will completely react with 167.6 grams of Fe?

IRISSAK [1]

Answer:
mass of S₈ = 96.1146 grams

Explanation:
The balanced equation that describe the reaction is as follows:
8 Fe + S₈ ..............> 8 FeS

From the equation, we can note that:
8 moles of Fe react with 1 mole of S₈
This means that:
8 * 55.8 grams of iron react with 8 * 32 grams of S₈.
To know the mass of S₈ that will react with 167.6 grams of Fe, we will simply do cross multiplication as follows:
mass of S₈ = (167.6 * 8 * 32) / (8 * 55.8)
mass of S₈ = 96.1146 grams

Hope this helps :)

5 0

3 years ago

3) What is the new strategy for disposing of nuclear waste? How is this strategy still dangerous?

kumpel [21]

Answer:

the newest strategy on get hurt a nuclear warhead we store any chemical agents is to actually dispose of them area of water lighten them off where there is no land animals or any other living breathing animals mammals plantations therefore the correct waste should be disposed of properly by either nuking it in like a loner thing when we burn bodies or in an isolated area where it cannot harm fellow American people animals tree life they should be disposed of properly properly by scientists that have corrected it and know how to break it down there for non giving harmful bacteria land my phone is going to die over Zone and taking away our atmosphere

4 0

3 years ago

Match each part of the electrochemical cell with its function.

umka21 [38]

Hi!

The correct options would be:

1. Cathode - <em>reduction</em>

The cathode is the negatively charged electrode, and so has an excess of electrons. Cations (positively charged ions) are attracted to the cathode, and gain electrons to acquire a neutral charge. The process in which a gain of electron occurs is called reduction.

2. Anode - <em>oxidation</em>

The opposite occurs at the anode which is positively charged and attracts negatively charged ions, anions. These anions lose their electrons at the anode to acquire a neutral charge, and the process involving loss of electrons is known as oxidation.

3. Salt Bridge - <em>ion transport </em>

Salt bridge is a physical connection between the the anodic and cathodic half cells in an electrochemical cell and is a pathway that facilitates the flow of ions back and forth these half cells. Salt bridge is involved in maintaining a neutral condition in the electrochemical cells, and its absence would result in the accumulation of positive charge in the anodic cell, and negative charge in the cathodic cell.

4. Wire - <em>electron transport </em>

Wires have a universal role of being a pathway for the transport of electrons in circuit. This role is also the same in the wires involved in an electrochemical cells where they are used to transport electrons from the anodic half cell, and this electron transport results in the generation of electricity in the internal circuit of the electrochemical cell.

Hope this helps!

4 0

3 years ago

How many milliliters of 0.500 M NaOH should be added to 10.0 g of tris hydrochloride (FM 121.135) to give a pH of 7.60 in a fina

liubo4ka [24]

Answer:

41.64mL of NaOH 0.500M must be added to obtain the desire pH

Explanation:

It is possible to find pH of a buffer by using H-H equation, thus:

pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of the weak acid TRIS-HCl and [A⁻] is concentration of its conjugate acid.</em>

Replacing in H-H equation:

7.60 = 8.072 + log [A⁻] / [HA]

0.3373 = [A⁻] / [HA] <em>(1)</em>

10.0g of TRIS-HCl (Molar mass: 121.135g/mol) are:

10.0g ₓ (1mol / 121.135g) = 0.08255 moles of acid. That means moles of both the acid and conjugate base are:

[A⁻] + [HA] = 0.08255 <em>(2)</em>

Replacing (1) in (2):

0.3373 = 0.08255 - [HA] / [HA]

0.3373[HA] = 0.08255 - [HA]

1.3373[HA] = 0.08255

<em>[HA] = 0.06173 moles</em>

Thus:

[A⁻] = 0.08255 - 0.06173 = 0.02082 moles [A⁻]

The moles of A⁻ comes from the reaction of the weak acid with NaOH, that is:

HA + NaOH → A⁻ + H₂O + K⁺

Thus, <em>you need to add 0.02082 moles of NaOH to produce 0.02082 moles of A⁻. </em>As NaOH solution is 0.500M:

0.02082 moles NaOH ₓ (1L / 0.500mol) = 0.04164L of NaOH 0.500M =

<h3>41.64mL of NaOH 0.500M must be added to obtain the desire pH</h3>

3 0

3 years ago

How many moles are in 442.8 g of strontium carbonate (SrCO3)?

GuDViN [60]

Answer:

3 moles

Explanation:

SrCO3

Mass = 442.8g

Molar mass = (87.6 + 12 * [16*3]) = 147.6g/mol

Number of moles = mass / molar mass

Number of moles = 442.8 / 147.6

Number of moles = 3

7 0

3 years ago