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mamaluj [8]
3 years ago
12

The rate law for a reaction is rate = k[A]2. What is the overall order of this reaction, and which two varaibles, when graphed,

will give a straight line for this reaction? A. first order, In[A]t versus t B. first order, 1/[A]t versus t C. second order, In[A]t versus t D. second order, 1/[A]t versus t
Chemistry
1 answer:
s2008m [1.1K]3 years ago
6 0

Answer:

D. second order, 1/[A]t versus t

Explanation:

Since the power of the concentration is 2 in the rate law, it is a second order reaction. Also, for a second order reaction, the variables that would yield a straight line when graphed are 1/[A]t versus t

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How many moles of N2 in 57.1 g of N2?
SpyIntel [72]

We are given –

  • Mass of \bf N_2 is 57.1 g and we are asked to find number of moles present in 57.1 g of \bf N_2

\qquad\pink{\bf\longrightarrow  { Molar \:mass \:of \: N_2:-}  }

\qquad\bf  \twoheadrightarrow 14\times 2

\qquad\bf \twoheadrightarrow   28

\qquad____________________

Now,Let's calculate the number of moles present in 57.1 g of \bf N_2

\qquad\purple{\bf\longrightarrow  { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}

\qquad\bf   \twoheadrightarrow \dfrac{57.1}{28}

\qquad\bf  \twoheadrightarrow 2.04\: moles

__________________________________

7 0
2 years ago
A homogeneous mixture is made by dissolving some salt in a beaker of water. The mixture is referred to as a
CaHeK987 [17]
In that case, the salt<span> would be the </span>solvent<span> and the </span>water<span> the </span><span>solute. 
So, it would be solution!

Have a nice day! :D</span>
3 0
3 years ago
Read 2 more answers
At a given temperature, the elementary reaction A − ⇀ ↽ − B , A↽−−⇀B, in the forward direction, is first order in A A with a rat
Svetllana [295]

Answer:

The equilibrium constant for the reversible reaction = 0.0164

Explanation:

At equilibrium the rate of forward reaction is equal to the rate of backwards reaction.

The reaction is given as

A ⇌ B

Rate of forward reaction is first order in [A] and the rate of backward reaction is also first order in [B]

The rate of forward reaction = |r₁| = k₁ [A]

The rate of backward reaction = |r₂| = k₂ [B]

(Taking only the magnitudes)

where k₁ and k₂ are the forward and backward rate constants respectively.

k₁ = 0.010 s⁻¹

k₂ = 0.0610 s⁻¹

|r₁| = 0.010 [A]

|r₂| = 0.016 [B]

At equilibrium, the rate of forward and backward reactions are equal

|r₁| = |r₂|

k₁ [A] = k₂ [B] (eqn 1)

Note that equilibrium constant, K, is given as

K = [B]/[A]

So, from eqn 1

k₁ [A] = k₂ [B]

[B]/[A] = (k₁/k₂) = (0.01/0.0610) = 0.0163934426 = 0.0164

K = [B]/[A] = (k₁/k₂) = 0.0164

Hope this Helps!!!

5 0
2 years ago
How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?
Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0
2 years ago
How can telescopes aid visualizing the electromagnetic spectrum?what is the “best place” for telescopes “to detect most radiatio
natima [27]

\huge \bold \red{question}

How can telescopes aid visualizing the electromagnetic spectrum?what is the “best place” for telescopes “to detect most radiation” and why?

\huge \bold \green{answer} \\

Astronomers use telescopes that detect different parts of the electromagnetic spectrum. Each type of telescope can only detect one part of the electromagnetic spectrum. There are radio telescopes, infrared telescopes, optical (visible light) telescopes and so on.

The best place to detect most radiation is above the blocking atmosphere, so some telescopes are put in orbit around the Earth. Even visible light is distorted by the atmosphere, so clearer pictures can be got from orbiting telescopes.

3 0
2 years ago
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