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nevsk [136]
3 years ago
12

The carbon cycle is powered by which two processes?

Physics
2 answers:
STALIN [3.7K]3 years ago
6 0

Answer:

Carbon-cycle is the cyclic process in which Carbon is  between different spheres of the Earth. Carbon is a major component of all the organic compounds as well as many minerals.  

Carbon is inter converted through the main processes: photosynthesis and respiration. Carbon dioxide incorporates in the living tissues through photosynthesis and is returned to the environment through the process of respiration, death and decay of living organisms etc.

Arada [10]3 years ago
4 0

Answer:

the answer is the last one

Explanation:

here is the definition:

(i know how to explain the answer, its merely unnecessary being that there is an offical definition.)

<em>the series of processes by which carbon compounds are interconverted in the environment, involving the incorporation of carbon dioxide into living tissue by photosynthesis and its return to the atmosphere through respiration, the decay of dead organisms, and the burning of fossil fuels.</em>

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<u>Answer:</u> The radiation emitted will have negligible mass number.

<u>Explanation:</u>

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3 years ago
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Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ
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Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

v=v_o+at    (1)

x=v_ot+\frac{1}{2}at^2   (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s

Next, you solve the equation (1) for the acceleration a:

a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

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