The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,
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The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.
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The balanced chemical equation for the standard formation reaction of liquid acetic acid as,
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The combustion of liquid acetic acid is given as,
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ΔH =-873
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Answer is: mass of calcium hydroxide is 46.98 grams.
Balanced chemical reaction: CaO + H₂O → Ca(OH)₂.
m(CaO) = 35.55 g.
n(CaO) = m(CaO) ÷ M(CaO).
n(CaO) = 35.55 g ÷ 56 g/mol.
n(CaO) = 0.634 mol; limiting reactant.
m(H₂O) = 125 mL · 1.000 g/mL.
m(H₂O) = 125 g.
n(H₂O) = 125 g ÷ 18 g/mol.
n(H₂O) = 6.94 mol.
From chemical reaction: n(CaO) : n(Ca(OH)₂) = 1 : 1.
n(Ca(OH)₂) = 0.634 mol.
m(Ca(OH)₂) = 0.634 mol · 74.1 g/mol = 46.98 g.
That answer for that question is B
Answer: Isotope Oxygen 18 will remain the same before and after the reaction because the amount of neutrons are the same in a isotope
Explanation:
Isotopes 18-17 and 16 are the most stable in earth. Keep in mind that a Isotope is an atom that has equal amount of protons and electrons but neutrons ( as you can see in the imagine below) . That is why, an isotope like oxygen 18 will remain the same in a chemical reaction, because there is only a electron transfer when doing a new molecule.
