Answer:
1.41s
5.95m/s
0.2746m
Explanation:
The time period
T = 1/f
= 1/0.709s
= 1.41 seconds
We have
T = 2π√l/g
T² = 4π²l/g
g = 4π²l/T²
g = 4x3.14²x0.300/1.41²
g = 5.95m/s² this is the acceleration due to gravity.
Then the time period of the glide
T2 = 2π√m/k
Length of pendulum = l
Time period T
T2 = 2π√l/g
Then T1 = T2
2π√m/k = 2π√l/g
M/k = l/g
L = g.m/k
L = 5.95x0.450/9.75
L = 0.2746
This must be the length of the simple pendulum
Answer:
The average force has a magnitude 6524 N due north.
Explanation:
The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.
a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)
v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s
a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s
Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.
The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N
Since the acceleration is due north, the average force takes the direction of the acceleration.
So the direction of the average force is due north
The average force has a magnitude 6524 N due north.
The object shown is a convex mirror. A convex mirror has a reflective surface and the body of it is curved outwards, it is used in sunglasses, security areas, telescopes, and magnifying glass.
Answer:
Third and fourth diagrams correctly represent the forces as vectors.
Explanation:
The vehicles are pulling against each other, this means their force vectors must point in the opposite directions, so our diagram must have this property.
Looking a the first diagram we see than both force vectors point in the same direction, so this cannot be the right answer.
In the second diagram the force vectors have the same direction, but in direction opposite the previous diagram. This is also not a correct diagram for our situation.
In the third diagram the forces vectors point in the opposite directions and they have the right magnitudes ( 750N is smaller than 1000N vector). So this diagram correctly represents our situation.
For the fourth diagram the vectors point in the opposite directions and they have the right magnitudes; therefore, it is also a correct representation of the situation.
So we have got two correct diagrams: the third and fourth. <em>And we cannot choose between them because we do not know whether it's the truck or the car that is on the left or right. For example if the car was on the left the third diagram would have been chosen. </em>
