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Illusion [34]
3 years ago
15

An object, 5 cm high, is placed on the principal axis of a diverging lens of focal length 20 cm. The object is 30 cm from the le

ns.
Use a scaled diagram to locate the image formed by the lens.
Physics
1 answer:
Nata [24]3 years ago
3 0

Answer:

The answer is 70 cm

Explanation:

If you add All the numbers together, you receive an 55 cm then you add 15 because the points on the diagram also count.

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What is the unit for molar mass?
dmitriy555 [2]

Answer:

kilogram per mole

Explanation:

ffdddddfsds

8 0
3 years ago
Read 2 more answers
claculate the pressure exerted by the water on the bottom of a deep dam of 12m from its surface .(density of water =1000kg/m sqa
Rudiy27

Explanation:

We know that,

hydrostatic \: pressure (p) =   \alpha hg

Where,

\alpha  = density \: of \: water \:  = 1000

h = Height at which pressure is to be calculated

p = 1000 \times 12 \times 9.8 = 117600 \:

8 0
3 years ago
In the javelin throw at a track-and-field event, the javelin is launched at a speed of 29 m/s at an angle of 36???? above the ho
netineya [11]

Answer:

t = 0.96 s  is the time it takes for the angle to reduce

Explanation:

In the launch of projectiles, the velocity is broken down into its x and y components, the velocity in the x-axis is constant, as there is no acceleration, instead the velocity in the axis and is reduced by the effect of the acceleration of gravity.

We can find Vox for the initial conditions

  Voy  = Vo sin θ

  Voy = 29 sin 36

  VoY = 17 m/s

  Vox = Vo cos θ

  Vox = 29 cos 36

  Vox= 23.5 m/s

  Vx = Vox  

The velocity on the x axis is constant

By trigonometry, we find the firing angle

 

  tan θ = Voy/ Vx

  Vy = Vx tan θ

  Vy = 23.5 tan 18

  Vy = 7.64 m/s

Now that we have the vertical speed we can find the time

   Vy = I'm going - g t

   t = (Vy -Voy) / g

   t = (17 - 7.64) /9.8

   t = 0.96 s

Be the time it takes for the angle to reduce

6 0
3 years ago
A train travels 8.81 m/s in a -51.0° direction.
Bad White [126]

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

  • θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

The displacement of the train is the change in position of the train after a given period of time.

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

5 0
2 years ago
Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

7 0
4 years ago
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