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Illusion [34]
3 years ago
15

An object, 5 cm high, is placed on the principal axis of a diverging lens of focal length 20 cm. The object is 30 cm from the le

ns.
Use a scaled diagram to locate the image formed by the lens.
Physics
1 answer:
Nata [24]3 years ago
3 0

Answer:

The answer is 70 cm

Explanation:

If you add All the numbers together, you receive an 55 cm then you add 15 because the points on the diagram also count.

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How to do this question
Yuki888 [10]

Answer:

64°

Explanation:

The triangle is an isosceles triangles (both legs are equal to the radius of the circle), so that means the base angles are the same.

Angles of a triangle add up to 180°, so:

128 + 2x = 180

2x = 52

x = 26

∠1 is complementary to the base angle, so:

∠1 = 90 − 26

∠1 = 64

7 0
3 years ago
You drive 200 miles in 3 hours before stopping for lunch and gas. After lunch you
Paraphin [41]

Given :

You drive 200 miles in 3 hours before stopping for lunch and gas. After lunch you  travel 250 miles in an hour and a half.

To Find :

Average speed.

Solution :

We know, average speed is given by :

v=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v=\dfrac{200+250}{3+1.5}\ miles/hr\\\\v=\dfrac{450}{4.5}\ miles/hr\\\\v=100\ miles/hr

Therefore, average speed of the journey is 100 miles/hr.

Hence, this is the required solution.

4 0
4 years ago
18. Two objects, X and Y. accelerate from rest with the same constant acceleration. Object X accelerates for
zvonat [6]

Answer:

e. Object X has traveled four times as far as object Y.

Explanation:

The distance covered by an object in uniform accelerated motion is given by:

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

The two objects in the problem have same initial velocity, u = 0 (since they start from rest), so we can rewrite the equation as

d=\frac{1}{2}at^2

We see that the distance covered is proportional to the square of the time. In this problem, the two objects X and Y have same acceleration, but object X accelerates for twice the time: since d \propto t^2, this means that the distance covered by X will be 2^2 = 4 times higher that the distance covered by object Y.

4 0
3 years ago
10-kg box is sliding across an ice rink at 10 m/s . A skater exerts a constant force of 10 N against it. How long will it take f
Taya2010 [7]

Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

7 0
3 years ago
Ask Your Teacher A trough is 16 ft long and its ends have the shape of isosceles triangles that are 2 ft across at the top and h
zloy xaker [14]

Answer:0.210 ft/min

Explanation:

Given

Length of trough L=16 ft

width of base b=2 ft

height of triangleh=1 ft

From Similar triangles property

\frac{4}{2x}=\frac{1}{y}

2y=x

volume of water in time t

V=\frac{1}{2}\times (2x\cdot y)\cdot

V=16xy

V=32y^2

differentiating

\frac{\mathrm{d} V}{\mathrm{d} t}=32\times 2\times y\times \frac{\mathrm{d} y}{\mathrm{d} t}

at y=8 in.\approx 0.667 ft

9=64\times 0.667\times \frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{9}{64\times 0.667}

\frac{\mathrm{d} y}{\mathrm{d} t}=0.210 ft/min

6 0
4 years ago
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