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juin [17]
3 years ago
9

The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second

, on the surface of the Sun?
Physics
1 answer:
just olya [345]3 years ago
8 0

Answer:

g=274\ m/s^2

Explanation:

Mass of the Sun, M=1.99\times 10^{30}\ kg

The radius of the Sun, r=6.96\times 10^8\ m

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2

So, the value of acceleration due to gravity on the Sun is 274\ m/s^2.

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A proton is released in a uniform electric field, and it experiences an electric force of 5 X 10^-10 N toward the South. What is
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Which is brighter in our sky, a star with apparent magnitude 2 or a star with apparent magnitude 7?
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The star with apparent magnitude 2 is more brighter than 7.

To find the answer, we have to know about apparent magnitude.

<h3>What is apparent magnitude?</h3>
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  • The apparent magnitude of bigger stars is always smaller.
  • The brightest star in the night sky is Sirius.
  • The brightness of a star or other celestial object perceived from Earth is measured in apparent magnitude (m).
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Thus, we can conclude that, the star with apparent magnitude 2 is more brighter than 7.

Learn more about the apparent magnitude here:

brainly.com/question/350008

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