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DochEvi [55]
3 years ago
11

Newton's second law of motion says that the mass of an object times its acceleration is equal to the net force on the object. Wh

ich of the following gives the correct units for force? a. Kg m^2/s^2 b. kg/m s^2 c. kg m/s^2 d. kg m^2/s e. none of these answers
Physics
1 answer:
insens350 [35]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

According to the second law of motion mass of an object times its acceleration is equal to the net force on the object.

Mathematically,     F = ma

Generally, mass is expressed in kilograms (kg) and acceleration is expressed as follows.

            acceleration = \frac{velocity}{time}

                                  = \frac{m/s}{s}

                                  = ms^{-2}

Hence, S.I unit of acceleration is ms^{-2}.

Therefore, units of force will be as follows.

                      F = ma

                         = kg \times ms^{-2}

Thus, we can conclude that kg \times ms^{-2} gives the correct units for force.

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b is your answers in this thread

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2 years ago
According to one set of measurements, the tensile strength of hair is 196 MPa , which produces a maximum strain of 0.380 in the
slega [8]

Answer:

(a). The magnitude of the force is 0.38416 N.

(b). The original length is 0.0869 m.

Explanation:

Given that,

Tensile strength = 196 MPa

Maximum strain = 0.380

Diameter = 50.0 μm

Length = 12.0 cm

We need to calculate the area

Using formula of area

A=\dfrac{\pi}{4}\times d^2

Put the value into the formula

A=\dfrac{\pi}{4}\times(50.0\times10^{-6})^2

A=1.96\times10^{-9}\ m^2

We need to calculate the magnitude of the force

Using formula of force

F=\sigma A

Put the value into the formula

F=196\times10^{6}\times1.96\times10^{-9}

F=0.38416\ N

(b). If the length of a strand of the hair is 12.0 cm at its breaking point

We need to calculate the unstressed length

Using formula of strain

strain=\dfrac{\Delta l}{l_{0}}

\Delta l=strain\times l_{0}

Put the value into the formula

\Delta l=0.380\times l_{0}

Length after expansion is 12 cm

We need to calculate the original length

Using formula of length

l=l_{0}+\Delta l

Put the value into the formula

I=l_{0}+0.380\times l_{0}

l=1.38l_{0}

l_{0}=\dfrac{l}{1.38}

l_{0}=\dfrac{12\times10^{-2}}{1.38}

l_{0}=0.0869\ m

Hence, (a). The magnitude of the force is 0.38416 N.

(b). The original length is 0.0869 m.

4 0
4 years ago
If the mass of a material is 42 grams and the volume of the material is 15 cm^3, what would the density of the material be?
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Density = mass / volume

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Answer:

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Explanation:

Applying the Equation of motion;

s = 0.5(u+v)t

Where;

s = distance travelled

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v = Final speed = 50 mph

t = time taken = 3/4 min = 3/4 ÷ 60 hours = 1/80 hour

Substituting the given values into the equation;

s = 0.5(0+50)×(1/80)

s = 0.3125 miles

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