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DochEvi [55]
3 years ago
11

Newton's second law of motion says that the mass of an object times its acceleration is equal to the net force on the object. Wh

ich of the following gives the correct units for force? a. Kg m^2/s^2 b. kg/m s^2 c. kg m/s^2 d. kg m^2/s e. none of these answers
Physics
1 answer:
insens350 [35]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

According to the second law of motion mass of an object times its acceleration is equal to the net force on the object.

Mathematically,     F = ma

Generally, mass is expressed in kilograms (kg) and acceleration is expressed as follows.

            acceleration = \frac{velocity}{time}

                                  = \frac{m/s}{s}

                                  = ms^{-2}

Hence, S.I unit of acceleration is ms^{-2}.

Therefore, units of force will be as follows.

                      F = ma

                         = kg \times ms^{-2}

Thus, we can conclude that kg \times ms^{-2} gives the correct units for force.

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maxonik [38]

probabilityAnswer:

2/27

Explanation:

The elk can not be eaten so we remove that from the probablity

so we have x/18

songbird = 4/18

mice = 6/18

4/18*6/18 = 2/27

5 0
2 years ago
How many neutrons does element x have if it’s atomic number is 23 and it’s mass is 90
Oxana [17]

The amount of neutrons would be 23.

The atomic number represents the amount of neutrons, so all you have to do is look at it to know. The atomic mass was put here simply to mislead you. B.T.W, the element is Valadium.

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3 0
4 years ago
Two forces F1 and F2 are acting on the box shown in the drawing, causing the box to move across the floor. The two force vectors
SpyIntel [72]

Answer: The correct answer is (b) F1 does more work than F2.

The block is moving horizontally the direction is opposite to direction of motion. The two forces applied are F1 and F2.F1 is applied horizontally so its horizontal component is F1cos0 = F1

While F2 is at angle  so horizontal component of F2 is F2cos(theta) and as we know cos is a decreasing in 0 to 90 degree. Therefore F1 does more work than F2.

Work is defined as the product of the magnitude of a force and the displacement of the object it is acting upon. In this case, the forces F1 and F2 are acting on the box, causing it to move across the floor. To calculate the work done by each force, we need to calculate the magnitude of the force and the displacement of the box.

The magnitude of F1 is given in the diagram, and it is 2 N. The magnitude of F2 is also given, and it is 4 N. For the displacement of the box, we will assume it is 1 m.

Now we can use the formula W = F x d to calculate the work done by each force.

For F1: W1 = 2 N x 1 m = 2 J

For F2: W2 = 4 N x 1 m = 4 J

Since F1 does 2 J of work, and F2 does 4 J of work, F1 does more work than F2 does. Therefore, the correct answer is (b) F1 does more work than F2 does.

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7 0
1 year ago
The intensity of electromagnetic waves from the sun is 1.4kW/m2 just above the earth's atmosphere. Eighty percent of this reache
Arlecino [84]

Answer:

E=8.02*10^{5}J

Explanation:

Given data

Electromagnetic waves from the sun is I=1.4kW/m² at 80%

Area a=(0.30×0.51)m²

Time t=1.30 hr

To find

Energy E

Solution

The energy received by your back is calculated as:

E=Pt=Iat\\E=(0.80)(1400W/m^{2} )(0.30*0.51m^{2} )(1.30*3600s)\\E=8.02*10^{5}J

3 0
3 years ago
Read 2 more answers
How long does it take electrons to get from
OlgaM077 [116]

We need to find the time it takes an electron to move in the given circuit.

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

I = Current = 134 A

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

A = Area = 38.9\ \text{mm}^2

L = Length = 92.2 cm

\rho = Density of copper = 8960\ \text{kg/m}^3

M = Molar mass of copper = 63.5 g/mol

n_v = Number of valence electrons of copper = 1

e = Charge of electron = 1.6\times 10^{-19}\ \text{C}

Number of charge carriers per unit volume is given by

n=\dfrac{\rho N_An_v}{M}\\\Rightarrow n=\dfrac{8960\times 6.022\times 10^{23}\times 1}{63.5\times 10^{-3}}\\\Rightarrow n=8.497\times 10^{28}\ \text{m}^{-3}

Time taken is given by

t=\dfrac{LAne}{I}\\\Rightarrow t=\dfrac{92.2\times 10^{-2}\times 38.9\times 10^{-6}\times 8.497\times 10^{28}\times 1.6\times 10^{-19}}{134}=3638.83\ \text{s}\\\Rightarrow t=\dfrac{3638.83}{60}=60.65\ \text{minutes}

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

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2 years ago
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