All categories

3 years ago

I MARK BRAINLIEST :D

Physics

2 answers:

ludmilkaskok [199]3 years ago

8 0

It’s Newton’s law of motion. his first law of motion or could be third law of motion

olganol [36]3 years ago

3 0

Answer:

Explanation:

its a chair that spins around

You might be interested in

3. The nervous system works together to communicate with different parts of the body and with the external environment. Spinal c

Likurg_2 [28]

Answer:

C. mediates communication from the brain to the rest of the body

Explanation:

The brain and spinal cord are your body's central nervous system. The brain is the command center for your body, and the spinal cord is the pathway for messages sent by the brain to the body and from the body to the brain.

7 0

4 years ago

Read 2 more answers

If the pendulum is taken into the orbiting space station what will happen to the bob? if the pendulum is taken into the orbiting

mezya [45]

Check the attached file for the answer.

3 0

4 years ago

A machine has a mechanical advantage of 5. What force should be applied to the machine to make it apply 3000 N to an object?

ziro4ka [17]

The answer to this very question is 3000n

6 0

3 years ago

Read 2 more answers

A model rocket is launched straight upward with an initial speed of 52.0 m/s. It accelerates with a constant upward acceleration

JulsSmile [24]

Explanation:

(a) After the engines stop, the rocket reaches a maximum height at which it will stop and begin to descend in free fall due to gravity.

(b) We must separate the motion into two parts, when the rocket's engines is on and when the rocket's engines is off.

First we must find the rocket speed when the engines stop:

$v_f^2=v_0^2+2ay_1\\v_f^2=(52\frac{m}{s})^2+2(1\frac{m}{s^2})(160m)\\v_f^2=3024\frac{m^2}{s^2}\\v_f=\sqrt{3024\frac{m^2}{s^2}}=54.99\frac{m}{s}$

This final speed is the initial speed in the second part of the motion, when engines stop until reach its maximun height. Therefore, in this part the final speed its zero and the value of g its negative, since decelerates the rocket:

$v_f^2=v_0^2+2gy_{2}\\y_{2}=\frac{v_f^2-v_0^2}{2g}\\y_{2}=\frac{0^2-(54.99\frac{m}{s})^2}{2(-9.8\frac{m}{s^2})}=154.28m$

So, the maximum height reached by the rocket is:

$h=y_1+y_2\\h=160m+154.28m=314.28m$

$v_f=v_0+at_1\\t_1=\frac{v_f-v_0}{a}\\t_1=\frac{54.99\frac{m}{s}-52\frac{m}{s}}{1\frac{m}{s^2}}\\t_1=2.99s$

And in the second part:

$t_2=\frac{v_f-v_0}{g}\\t_2=\frac{0-54.99\frac{m}{s}}{-9.8\frac{m}{s^2}}\\t_2=5.61s$

So, the time it takes to reach the maximum height is:

$t_3=t_1+t_2\\t_3=2.99s+5.61s=8.60s$

(d) We already know the time between the liftoff and the maximum height, we must find the rocket's time between the maximum height and the ground, therefore, is a free fall motion:

$v_f^2=v_0^2+2ay\\v_f^2=0^2+2(9.8\frac{m}{s^2})(314.28m)\\v_f=\sqrt{6159.888\frac{m^2}{s^2}}=78.48\frac{m}{s}$

$t_4=\frac{v_f-v_0}{g}\\t_4=\frac{78.48\frac{m}{s}-0}{9.8\frac{m}{s^2}}\\t_4=8.01s$

So, the total time is:

$t=t_3+t_4\\t=8.60s+8.01s\\t=16.61s$

7 0

4 years ago

Select all that Apple

egoroff_w [7]

B is the correct answer since acid corrode on metals such as carbon, steel, zinc and such.

6 0

4 years ago