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grin007 [14]
3 years ago
7

Hey if you talk to me i will mark you as a brainliest and if you answer all my question

Physics
2 answers:
Fittoniya [83]3 years ago
5 0

Answer:

<u>what</u><u> </u><u>will</u><u> </u><u>happen</u><u> </u><u>if</u><u> </u><u>i</u><u> </u><u>will</u><u> </u><u>answer</u><u> </u><u>ur</u><u> </u><u>questions</u><u>?</u>

Explanation:

is there gonna be a bad thing or a good thing

olya-2409 [2.1K]3 years ago
5 0
Answer: hello! The correct answer is a. How are you? hope all is well! Have a great day! Merry Christmas! :)
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In a computer simulation, Juan moves a magnet (Magnet 1) closer to another magnet (Magnet 2) that cannot move. Which statement a
tekilochka [14]

Answer:

C

Explanation:

The potential energy decreases because Magnet 1 moves against the magnetic force. If it was increased it would be kinetic

8 0
3 years ago
Read 2 more answers
van object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.0
creativ13 [48]

Initial velocity of object vi=10.0 cm/s

initial position fo vector of the object is xi=3.09 cm

Final position of vector xf=-5.00cm

then displacement of object s = xf-xi=-5.00-3.09=-8.09cm

time t=2.55 s

s=vit+1/2at2

-5.00 = 11*2.55+1/2*a2.552

a = (-5.00 - 10*2.55*2)/2.552 = 2.94 cm

Acceleration is 2.94 cm.

<h3>What is acceleration?</h3>

Speed increase is the name we provide for any cycle where the speed changes. Since speed is a speed and a bearing, there are simply two different ways for you to speed up: change your speed or shift your course or change both. In mechanics, speed increase is the pace of progress of the speed of an item concerning time. Speed increases are vector amounts. The direction of an item's speed increase is given by the direction of the net power following up on that article. An item's typical speed increase throughout some stretch of time is its adjustment of speed separated by the term of the period. Numerically, quick speed increase, in the meantime, is the constraint of the typical speed increase over a little time period. In the terms of analytics, immediate speed increase is the subordinate of the speed vector concerning time.

Learn more about acceleration, refer:

brainly.com/question/27973611

#SPJ4

4 0
2 years ago
A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back
Kobotan [32]

Answer:

a) 5 m/s

b) 17.8542 m/s

c) 24.7212 m/s

0.229

Explanation:

t = Time taken

u = Initial velocity = 5 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=5-9.81\times t\\\Rightarrow \frac{-5}{-9.81}=t\\\Rightarrow t=0.51 \s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=5\times 0.51+\frac{1}{2}\times -9.81\times 0.51^2\\\Rightarrow s=1.27\ m

So, the stone would travel 1.27 m up

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.27+0^2}\\\Rightarrow v=5\ m/s

Velocity as the rock passes through the original point is 5 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 1.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.27\times 2}{9.81}}\\\Rightarrow t=0.51\ s

Time taken to reach the original point is 0.51+0.51 = 1.02 seconds

So, total height of the rock would fall is 30+1.27 = 31.27 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 16.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{16.27\times 2}{9.81}}\\\Rightarrow t=1.82\ s

Time taken by the stone to reach 15 m above the ground is 1.82+0.51 = 2.33 seconds

v=u+at\\\Rightarrow v=0+9.81\times 1.82\\\Rightarrow v=17.8542\ m/s

Speed of the ball at 15 m above the ground is 17.8542 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 31.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{31.27\times 2}{9.81}}\\\Rightarrow t=2.52\ s

v=u+at\\\Rightarrow v=0+9.81\times 2.52\\\Rightarrow v=24.7212\ m/s

Speed of the stone just before it hits the street is 24.7212 m/s

F = Force

m = Mass = 100 kg

g = Acceleration due to gravity = 9.81 m/s²

s = Displacement = 4 km = 4000 m

P = Power = 1 hp = 745.7 Watt

t = Time taken = 20 minutes = 1200 seconds

μ = Coefficient of sliding friction

F = μ×m×g

⇒F = μ×100×9.81

W = Work done = F×s

P = Work done / Time

⇒P = F×s / t

745.7=\frac{\mu \times 981\times 4000}{1200}\\\Rightarrow \mu=\frac{747.5\times 1200}{981\times 4000}\\\Rightarrow \mu=0.229

Coefficient of sliding friction is 0.229

8 0
3 years ago
Drew observed in an experiment that algae in a nearby lake could be found at six meters below the water's surface on a clear day
babymother [125]

In this question the options are missing; here are the options:

What was the dependent variable in Drew's experiment?

A. The depth at which the algae were found

B. The sky conditions on a particular day

C. The amount of algae measured

D. The lake that was being observed

The answer to this question A. The depth at which the algae were found

Explanation:

In an experiment, it is common there are at least two factors or variables. Additionally, the variable that is modified by others or that depend on others is always the dependent variable.

In the case of the experiment presented, there are two main factors: sky conditions and depth at which algae can be found. From these, the dependent factor is the depth because this depth changes with the sky condition or depends on the sky conditions. Also, the dependent variable is always the factor being studied, for example, in this case, Drew's focus is to study how the location of algae in terms of depth changes.

8 0
3 years ago
Read the excerpt from Neil deGrasse Tyson’s “Death by Black Hole.” Black holes are regions of space where the gravity is so high
kramer
<h2>Answer: a definition of the term black hole</h2>

This text is clearly a definition of the term black hole, made by the American astrophysicist Neil deGrasse Tyson.

However, the discussions about this subject are not new, since Einstein's theory of relativity already defined what a black hole is.

In this sense, a black hole is described as a "singularity" that consists of <u>a region of the space in which the density of matter tends to infinity.</u>

Although this is hard to find possible for classical physics; following what relativity establishes:<em> bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved. </em>

4 0
3 years ago
Read 2 more answers
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