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Bingel [31]
3 years ago
15

X^2+6X=16 is a quadratic equation what are the solutions?

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0
x^2+6x=16\\\\ (x+3)^2-9=16\\\\ (x+3)^2=5^2\\\\x+3=5 \ or x+3=-5\\\\ x=2\\\\or x=-8 
IgorC [24]3 years ago
4 0
The answer is 2,-8.
But I am not sure. Hope this will help you!
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A new car sells for $18,000 but it will depreciate over time. After just one year,
WITCHER [35]

Answer:

a.) 18000 x (0.88)^x

x=number of years

b.) value after 10 yrs is represented by

18000 x (0.88)^10 = about $5013

Step-by-step explanation:

8 0
3 years ago
How do you solve for y?
Igoryamba
I dont know if this help you or not

8 0
2 years ago
Need help me please don't know this
motikmotik

Answer:

c.9

the correct answer

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2 years ago
Read 2 more answers
Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
Rewrite 3* = 243 as a logarithmic equation.
soldi70 [24.7K]

Answer:

log₃(243) = x

Step-by-step explanation:

3^x = 243

Rule: a^x = b -> logₐ(b) = x

log₃(243) = x

4 0
2 years ago
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