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Bogdan [553]
3 years ago
6

A 1-inch length in the scale drawing below corresponds to a length of 12 feet in the actual room. Describe how the scale or the

scale factor can be used to determine the area of the actual dining room.
Mathematics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

Step-by-step explanation:lol you think I know I hate this app

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Someone please help me <br> serious answers only!!!!!
12345 [234]
The answer to your question is C.
3 0
3 years ago
HELPPPPPPPPPPP
liubo4ka [24]
<span>(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.

cos 49 = ground / plank
cos 49 = 3 / plank
plank = cos 49 / 3
plank = 0.10 ft

</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
</span><span>
The remaining angle is equal to
angle = 180 - (90+49)
angle = 41

Finding the height.
tan 41 = height / ground
tan 41 = height / 3
height = tan 41 / 3
height = 0.05 ft.

(A) 0.10 feet
(B) 0.05 feet</span>
3 0
4 years ago
A test consists of 10 multiple choice questions, each with five possible answers, one of which is correct. To pass the test a st
Softa [21]

Answer:

0.006369

Step-by-step explanation:

Given that a test consists of 10 multiple choice questions, each with five possible answers, one of which is correct.

By mere guessing p = probability for a right answer = 1/5 =0.20

There are two outcomes and each question is independent of the other.

X no of questions right is Bin (10,0.20)

the probability that the student will pass the test

= prob of getting more than 60%

=P(X\geq 6)

=0.006369

8 0
4 years ago
PLEASE PLEASE I NEED HELP ON THIS ASAP
Alisiya [41]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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