269,937 hope this helps!!
Answer:
24.525 g of sulfuric acid.
Explanation:
Hello,
Normality (units of eq/L) is defined as:
Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:
Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:
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We use the following formula for calculating the density:
p = m/v
Where:
m = mass
v = volume
So, we have:
p = 46 /5
p = 9,2 g/cm³
.605862g H2
To find this, set up the following equation:
You're starting with 23.5 grams of potassium and you want to end up with grams of Hydrogen. To do that, you need to do a molar ratio:
23.5gK
Multiply everything on the top (23.5 x 1 x 1 x 2.016) and on the bottom (39.098 x 2 x 1).
Divide the product given from the top, 47.376, by the product from the bottom, 78.196 to get the final mass of .605862 or rounded up to .606
The reason for the molar ratio is because in the given equation, you need to take into account the needed amount of moles for each element/compound. You also cannot just go from grams to grams, you must have a conversion of moles in between just as you would for grams to molecules.
Hope this helps!