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Citrus2011 [14]
3 years ago
13

Suppose you have two cubes of exactly the same volume. You weigh them and find a mass of 8.91g for one and 8.88g for the other c

ube even though they are made of the same material. How is this possible? ANSWER FAST
Chemistry
2 answers:
Blababa [14]3 years ago
7 0

Explanation:

Mass of the cube -1 = 8.91 g

Mass of  the cube-2 = 8.88 g

Volume of the cube-1 = Volume of cube-2 = V

Density of the cube-1 = D

Density of cube-2 = D'

Density=\frac{Mass}{Volume}

D=\frac{8.91 g}{V}

D'=\frac{8.88 g}{V}

\frac{D}{D'}=\frac{\frac{8.91 g}{V}}{\frac{8.88 g}{V}}=1.0033

D=1.0033\times D'

Density directly depends upon mass of the substance and inversely depends upon volume of the substance.

Here volume of the both cubes are same but masses are different. So, in this case densities of both cubes can be compared on the basis of masses.

This difference in densities of same material can be due following possibles:

1. May be an impurity present in the one of the cubes for which they have given different values their mass.

2. Weighing may not be working well.

3. May be an air trapped inside in one of the cubes.

Yuliya22 [10]3 years ago
3 0
The two substances have different densities. Density can be affected by the temperature of a substance. Since they have to same volume but weigh differently, they have different densities. Remember, density = mass/volume
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svetlana [45]

Answer:

a. 3; b. 5; c. 10; d. 12

Explanation:

pH is defined as the negative log of the hydronium concentration:

pH = -log[H₃O⁺] (hydronium concentration)

For problems a. and b., HCl and HNO₃ are strong acids. This means that all of the HCl and HNO₃ would ionize, producing hydronium (H₃O⁺) and the conjugate bases Cl⁻ and NO₃⁻ respectively. Further, since all of the strong acid ionizes, 1 x 10⁻³ M H₃O⁺ would be produced for a., and 1.0 x 10⁻⁵ M H₃O⁺ for b. Plugging in your calculator -log[1 x 10⁻³] and -log[1.0 x 10⁻⁵] would equal 3 and 5, respectively.

For problems c. and d. we are given a strong base rather than acid. In this case, we can calculate the pOH:

pOH = -log[OH⁻] (hydroxide concentration)

Strong bases similarly ionize to completion, producing [OH⁻] in the process; 1 x 10⁻⁴ M OH⁻ will be produced for c., and 1.0 x 10⁻² M OH⁻ produced for d. Taking the negative log of the hydroxide concentrations would yield a pOH of 4 for c. and a pOH of 2 for d.

Finally, to find the pH of c. and d., we can take the pOH and subtract it from 14, giving us 10 for c. and 12 for d.

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2 years ago
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shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

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Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

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3 years ago
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Answer:

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