Answer:
v = 2917.35 m/s
Explanation:
let Fc be the centripetal force avting on the satelite , Fg is the gravitational force between mars and the satelite, m is the mass of the satelite and M is the mass of mars.
at any point in the orbit the forces acting on the satelite are balanced such that:
Fc = Fg
mv^2/r = GmM/r^2
v^2 = GM/r
v = \sqrt{GM/r}
= \sqrt{(6.6708×10^-11)(6.38×10^23)/(3.38×10^6 + 1.62×10^6)}
= 2917.35 m/s
Therefore, the orbital velocity of the satelite orbiting mars is 2917.35 m/s.
All of them are very expensive to install the machinery.
Nuclear energy has no particular negative effect while it's being
generated. But after the fuel is 'used up', and you can't get much
more energy out of it, it's still highly radioactive and dangerous to
people.
We still don't have a good, completely foolproof way to dispose of
the waste material, in a way that will protect people from it for as long
as it stays radioactive (can be thousands of years !).
Hello there.
The effective force is the horizontal component of tension T. The tension, by similar triangles, has as adjacent side that is the effective force. Hence, we conclude: