A man driving a car traveling at 20 m/sec slams on the brakes and decelerates at 3.25
1 answer:
Recall that
where and
are initial and final velocities, respectively;
is acceleration; and
is the net displacement, or distance if the object is moving in a single direction.
The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then
0² - (20 m/s)² = 2 (-3.25 m/s²) ∆<em>x</em>
∆<em>x</em> = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m
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while acceleration is defined as rate of change in velocity
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