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PilotLPTM [1.2K]
3 years ago
10

The radius of a circle is 35 centimeters.

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

3864.5

Step-by-step explanation:

I used 3.14 for pie, since its more common than 22/7.

To find the area of a circle: pir^2.

r=35

pi=3.14

35 times 35=1225

1225 times 3.14=3846.5

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the weight of a rock sample is measured to be 3.1 pounds. What is the percent of error in the measurement?
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He unit circle has a radius of 1 unit and is centered at the origin. It is dilated so that it passes through the point (4, 0).
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The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish,
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Answer:

1. There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2. There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

Step-by-step explanation:

The question is incomplete:

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish, bearish, and neutral on the stock market for the next six months. For the week ending November 7, 2012 the survey results showed 38.5% bullish, 21.6% neutral, and 39.9% bearish (AAII website, November 12, 2012). Assume these results are based on a sample of 300 AAII members.

1. This is a hypothesis test for a proportion.

The claim is that bullish sentiment differs from its long-term average of 0.39.

Then, the null and alternative hypothesis are:

H_0: \pi=0.39\\\\H_a:\pi\neq 0.39

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.385.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.39*0.61}{300}}\\\\\\ \sigma_p=\sqrt{0.000793}=0.028

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.385-0.39+0.5/300}{0.028}=\dfrac{-0.003}{0.028}=-0.118

This test is a two-tailed test, so the P-value for this test is calculated as:

P-value=2\cdot P(z

As the P-value (0.906) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2) This is a hypothesis test for a proportion.

The claim is that bearish sentiment is above its long-term average of 0.30.

Then, the null and alternative hypothesis are:

H_0: \pi=0.3\\\\H_a:\pi\neq 0.3

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.399.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{300}}\\\\\\ \sigma_p=\sqrt{0.0007}=0.026

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.399-0.3-0.5/300}{0.026}=\dfrac{0.097}{0.026}=3.679

This test is a two-tailed test, so the P-value for this test is calculated as:

P-value=2\cdot P(z>3.679)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

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