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PilotLPTM [1.2K]
3 years ago
10

The radius of a circle is 35 centimeters.

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

3864.5

Step-by-step explanation:

I used 3.14 for pie, since its more common than 22/7.

To find the area of a circle: pir^2.

r=35

pi=3.14

35 times 35=1225

1225 times 3.14=3846.5

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A pet store advertises
nikklg [1K]

Answer:

the answer is 1.99 I think im not sure I guessed

Step-by-step explanation:

5 0
3 years ago
Given that 10% of the nails made using a certain manufacturing process have a length less than 2.48 inches, while 5% have a leng
zvonat [6]

Answer:

The mean, μ is 2.5063 and

The standard deviation, σ = 2.0499 × 10⁻²

Step-by-step explanation:

Here we have

z = \frac{x- \mu}{\sigma}

z \sigma ={x- \mu}{} and

10% have length < 2.48 in while

5% have length > 2.54 in

and

From the z score table

Critical z at 10% to the left = -1.282

Critical z at 5% to the right = 1.645

Therefore, the equations become

-1.282σ = 2.48 - μ → μ -1.282σ = 2.48

1.645σ = 2.54 - μ → μ + 1.645σ = 2.54

Solving the above equations gives

The mean, μ = 2.5063 and

The standard deviation, σ = 2.0499 × 10⁻².

7 0
3 years ago
(1) 16 liters of kerosene is needed for 12 stoves 14
Nastasia [14]

9514 1404 393

Answer:

  12 liters

Step-by-step explanation:

The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...

  v = k·s·h . . . . . for s stoves running h hours

Then the value of k is ...

  k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour

Then the volume of kerosene required for 7 stoves and 18 hours is ...

  v = (2/21)·s·h

  v = (2/21)(7)(18) = 12 . . . liters

6 0
3 years ago
Solve for y.<br><br> y + 1.05 = 7.26<br> A.y = 8.31<br> B.y = -8.31<br> C.y = 6.21<br> D.y = -6.21
Lady bird [3.3K]

Answer:

The answer is C (6.21).

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the critical f-value when the sample size for the numerator is four and the sample size for the denominator is seven? us
fgiga [73]

Assuming that we are performing a two-tailed test, the significance level is α = 0.1 would be dispersed in the distribution's tails with α/2  = 0.05.

And we must consider two critical values that add up to 0.05 of a area on every tail of a F distribution with a 10 degree angle.

\begin{aligned}&F_{\alpha / 2}=0.311 \\&F_{1-\alpha / 2}=4.06\end{aligned}

<h3>What is critical f-value?</h3>

An F statistic is one that is ascertained through an ANOVA test. It helps determine the relevance of the variable groups.

Now, according to the question;

We understand that sample size for numerator is 11 and also the sample size for denominator is 7. So, for each case, we can calculate a degrees of freedom as follows:

\begin{aligned}&d f_{\text {num }}=11-1=10 \\&d f_{d e n}=7-1=6\end{aligned}

In this case, the F distribution could have 10 degrees of freedom with in numerator as well as 6 degrees of freedom in the denominator.

Assuming we are conducting a two-tailed test, the significance level of α = 0.1 will be distributed in the tails of the distribution with α/2  = 0.05.

Now, locate two critical values that collect 0.05 of a area on every tail of F distribution to 10 degrees of freedom again for numerator and 6 degrees of freedom for the denominator and we obtained using a table or excel;

\begin{aligned}&F_{\alpha / 2}=0.311 \\&F_{1-\alpha / 2}=4.06\end{aligned}

Therefore, the critical f-value for the two-tailed experiment is found.

To know more about the critical f-value, here

brainly.com/question/17164520

#SPJ4

5 0
1 year ago
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