The radius of a circle is 35 centimeters.

Mathematics

1 answer:

dem82 [27]3 years ago

6 0

Answer:

3864.5

Step-by-step explanation:

I used 3.14 for pie, since its more common than 22/7.

To find the area of a circle: pir^2.

r=35

pi=3.14

35 times 35=1225

1225 times 3.14=3846.5

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geniusboy [140]

Answer:

The series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' is;

C. Translation, translation

Step-by-step explanation:

The coordinates of points in pentagon FGHIJ are F(-2, 0), G(-1, 3), H(-2, 4), I(-5, 4), J(-4, 1)

The coordinates of points in pentagon F'G'H'I'J' are F'(2, 1), G'(3, 4), H'(2, 5), I(-1, 5), J(0, 2)

Therefore the series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' are;

1) A horizontal translation 4 units to the right and

2) A vertical translation 1 unit up

Therefore, the series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' is T₍₄, ₁₎ which is a translation, translation.

8 0

3 years ago

Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected.

Leno4ka [110]

As the problem indicates, degrees of freedom are the number of values that can be independently selected before it is necessary to choose specific values to arrive at the desired result.

The average, on the other hand, results from the sum of a list of values divided by the amount of values in the summed list.

Assume that the mean sought is $x$ and consider that the list is composed of a single element $a$ , in that case no random number can be selected, since the mean $x$ must correspond to that number.

If the list were composed of two elements $a$ and $b$ , one of the two values could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in $2x$ , this given that the formula of the average $\sum\limits_{i=1}^n \frac{ x_{i}}{n}$ .

With three values $a$ , $b$ and $c$ , it is possible to select two freely, since the thirteen must be the one that balances the sum of $a+b$ , that is $(a + b) + c = 3x$ .

Thus, in general, with n values, it is possible to select $n-1$ values freely whose sum must be balanced by the last value so that the whole sum is $nx$ .