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Alborosie
3 years ago
5

What is the [OH-] of a substance that has a pH of 11?

Chemistry
1 answer:
Deffense [45]3 years ago
6 0

Answer:

0.001 M OH-

Explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

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