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max2010maxim [7]
3 years ago
15

What are watts equal to?

Engineering
2 answers:
Elena L [17]3 years ago
5 0
Joules per second, one watt is converted to 1J/ S in a conversion I hope that helps!
Umnica [9.8K]3 years ago
4 0

Answer:

joules per second

equivalent to one ampere under a pressure of one volt.

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¿Cuál es el objetivo de la participación del gobierno en la economía?
Paul [167]

Answer:

la participación del Estado y del gobierno en la economía es fundamental. Las tareas o funciones del Estado en la economía son al menos: redistribución de la renta, estabilización de la economía, asignación de recursos, promoción del crecimiento, y regulación económica.

6 0
3 years ago
A wastewater is to be disinfected using ultraviolet (UV) light. Batch experiments find that the bacterial concentration decays u
Ksivusya [100]

Answer:

k = 0.1118 per min

Explanation:

Assume;

Initial number of bacteria = N0

Number of bacteria IN 'T' time = Nt

So,

Nt=N0e^{-kt}\\\\in\ 6.2 min\\\\\\frac{N0}{2}= N0e^{-k(6.2)}\\\\ln\frac{1}{2} = -k[6.2]

k = 0.1118 per min

7 0
3 years ago
Which option distinguishes the step in the engineering design phase described in the following scenario?
rewona [7]

Answer:

reasearching the problem

Explanation:

EDG

7 0
3 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
Aliun [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

5 0
3 years ago
How could increasing the budget for testing have prevented the problem experienced by the mars orbiter?
vlada-n [284]

Answer:

this might help

Explanation:

https://science.ksc.nasa.gov/mars/msp98/misc/MCO_MIB_Report.pdf

5 0
3 years ago
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