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max2010maxim [7]
3 years ago
15

What are watts equal to?

Engineering
2 answers:
Elena L [17]3 years ago
5 0
Joules per second, one watt is converted to 1J/ S in a conversion I hope that helps!
Umnica [9.8K]3 years ago
4 0

Answer:

joules per second

equivalent to one ampere under a pressure of one volt.

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On some late model cars, climate control systems wil create trouble codes for trouble shooting purposes.
Advocard [28]
I think it’s true because I mean that where you have air conditioner and stuff but as though it’s probably not codes but in a car there probably will be codes
8 0
3 years ago
if you’re disassembling a master cylinder and the front piston assembly is stuck in the master cylinder you can
lianna [129]

Answer:

Put water in the cylinder then push the piston inward

Explanation:

When water is put it displaces all the air making it possible for the piston to be pulled easier and without distraction

6 0
3 years ago
Construct a Mohr circle for the stress element at A in problem 2. Using ruler and compass, draw the Mohr circle to the scale. Dr
serious [3.7K]

Answer:

hello your question is incomplete attached below is the missing diagram to the question and the detailed solution

Answer : principal stresses : 0.82 MPa, -33.492 MPa

              shear stress = 17.157 MPa

              ∅ = 9.09 ≈ 10°

Explanation:

The principal stress ( б1 ) = 0.82 MPa

                                 ( б2 ) = -33.492 MPa

The shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

attached below is the detailed solution and the Mohr's circle

7 0
3 years ago
A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli
lukranit [14]

Answer:

For the Top Side

- Strain ε  = 0.00021739

- Elongation is 0.00260868 cm

For The Right side

- Strain ε  = 0.00021739

-Elongation is 0.00347826 cm

Explanation:

Given the data in the question;

Length of the squared titanium plate = 12 cm by 12 cm = 0.12 m by 0.12 m

Thickness = 5 mm = 0.005 m

Force to the Top F_t = 15 kN = 15000 Newton

Force to the right F_r = 20 kN = 20000 Newton

elastic modulus, E = 115 GPa = 115 × 10⁹ pascal

Now, For the Top Side;

- Strain = σ/E = F_t  / AE

we substitute

= 15000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 15000 / 69000000

Strain ε  = 0.00021739

- Elongation

Δl = ε × l

we substitute

Δl = 0.00021739 ×  12 cm

Δl = 0.00260868 cm

Hence, Elongation is 0.00260868 cm

For The Right side

- Strain = σ/E = F_r  / AE

we substitute

Strain = 20000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 20000 / 69000000

Strain ε = 0.000289855

- Elongation

Δl = ε × l

we substitute

Δl = 0.000289855×  12 cm

Δl = 0.00347826 cm

Hence, Elongation is 0.00347826 cm

5 0
3 years ago
Go to the sd_messier.html file. Within the document head, create links to the sd_base.css, sd_layout.css, and sd_effects.css sty
makkiz [27]

Answer:

Explanation:

1. Inside tss_coach.html <head> section, include these two lines of code:

<link rel="stylesheet" href="coach_layout.css">

<link rel="stylesheet" href="coach_styles.css">

These two lines links the CSS files with the HTML code.

2. Include the below two lines at the top of the file coach_styles.css and before the comment section

@charset "UTF-8"

@font-face { font-family: Nobile;

src: url (nobile-webfont.woff); }

6 0
3 years ago
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