Answer: True
Explanation:
Engineering stress is the applied load divided by the original cross-sectional area of a material. It is also known as nominal stress. It can also be defined as the force per unit area of a material. Engineering Stress is usually in large numbers.
While Engineering strain is the amount that a material deforms per unit length in a tensile test. It can also be defined as extension per unit length. It has no unit as it is a ratio of lengths. Engineering Strain is in small numbers.
Answer:
The following program is in C++.
#include <bits/stdc++.h>
using namespace std;
void lastChars(string s)
{
int l=s.length();
if(l!=0)
{
cout<<"The last character of the string is: "<<s[l-1];
}
}
int main() {
string s;//declaring a string..
getline(cin,s);//taking input of the string..
lastChars(s);//calling the function..
return 0;
}
Input:-
Alex is going home
Output:-
The last character of the string is: e
Explanation:
In the function lastChars() there is one argument that is a string.I have declared a integer variable l that stores the length of the string.If the length of the string is not 0.Then printing the last character of the string.In the main function I have called the function lastChars() with the string s that is prompted from the user.
Answer:
Q = 378.247 Bt/hr
Explanation:
given data:
diameter of container = 3 m
so r = 1.5 m
T1 = 50°C
T2 = 100°C
depth y = 3 ft
Heat transfer is given as Q
Where
S = Shape factor for the object
S = 25.132 ft
Q = 25.132*0.301 *(100-50)
Q = 378.247 Bt/hr
Answer:
0.124
Explanation:
We calculate the hydraulic gradient by the formulas below.
I = (change in h)/(change in l)-----eqn 1
I = (hk-hl)/change in L ----- equation 2
At k the headloss = hk,
At L the headloss = hL
The distance of water travel is change in I
Total head at k
hk = 543+23
= 566 ft
Total head at L
hL = 461+74
= 535 ft
Change in L = 250
When we substitute these values in equation 2
566-535/250
= 0.124
The hydraulic gradient is 0.124
