Answer:
Heat gain of 142 kJ
Explanation:
We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.
Δ
⇒
Δ

Therefore, the gas gained heat by an amount of 142 kJ.
Answer:
The mechanical gauge would be the one for the job
Explanation:
Answer:
HIGH from the supply voltage
LOW from ground
Explanation:
The answer depends on the kind of system and the purpose of the signal. But for practical reasons, in a DIGITAL system where 5V is HIGH and 0 V is LOW, 5 volts can be taken from the supply voltage (usually the same as high, BUT must be verified), and the LOW signal from ground.
If the user has a multimeter, it must be set to continuous voltage on 0 to 20 V range. Then place the probe in the ground of the circuit (must be a big copper area). Finally leave one probe in the circuit ground and place the other probe in some test points to identify 5 v.
Answer:
a. 430.944 pascal
b. 0.0625psi
c. 1.73008inH20
Explanation:
The pressure rise Ap associated with wind hitting a win- dow of a building can be estimated using the formula Ap-p(12/2), where p is density of air and V is the speed of the wind. Apply the grid method to calculate pressure rise for P-1.2 kg/m and V-60 mph. a. Express your answer in pascals. b. Express your answer in pounds-force per square inch (psi). c. Express your answer in inches of water column
checking the dimensional consistency
Dp=

convert 1 mile to meter
1mile=1609m
1h=3600s
60mile/h=26.8m/s
slotting intpo the relation

430.944kg/(ms^2)
which is the same as 430.944N/m^2
expressing in pascal.
We know that
1 pascal=1 N/m^2
430.944 pascal
2. 1 pascal=0.000145psi
answer=0.0625psi
3.1 pascal=0.00401inH20
answer=430.944*0.0040146
1.73008inH20