A block slides along a frictionless surface and onto a slab with a rough surface. The slab has mass of 4 kg and the block has ma
1 answer:
Answer: the friction force on the small block at t equals 1 second is 2N
Explanation:
Given the data in the question;
from the slope in the graph provided, we will get the acceleration of the slab
At t = 1 seconds
Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²
Force = ma = 4 × 0.5 = 2 N
so by Newton's third law
Force on block will be same which is 2N
Therefore the friction force on the small block at t equals 1 second is 2N
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Answer:
Change in kinetic energy = 3297280 J
Explanation:
Given that,
Mass, m = 920 kg
Speed of a car, v = 92 m/s
Kinetic energy, K = 3,893,440 J
If the speed of a car, V = 36 m/s
Net kinetic energy is given by :
The change in kinetic energy = 3,893,440 - 596160
= 3297280 J
So, the change in kinetic energy of the car is 3297280 J.
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