Answer: the friction force on the small block at t equals 1 second is 2N
Explanation:
Given the data in the question;
from the slope in the graph provided, we will get the acceleration of the slab
At t = 1 seconds
Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²
Force = ma = 4 × 0.5 = 2 N
so by Newton's third law
Force on block will be same which is 2N
Therefore the friction force on the small block at t equals 1 second is 2N
Answer:
Force of friction, f = 751.97 N
Explanation:
it is given that,
Mass of the car, m = 1100 kg
It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.
From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.
f = 751.97 N
So, the force of friction on the car is 751.97 N. Hence, this is the required solution.
Answer:
diameter = 9.951 × m
Explanation:
given data
NA = 0.1
refractive index = 1.465
wavelength = 1.3 μm
to find out
What is the largest core diameter for which the fiber remains single-mode
solution
we know that for single mode v number is
V ≤ 2.405
and v =
here r is radius
so we can say
= 2.405
put here value
= 2.405
solve it we get r
r = 4.975979 × m
so diameter is = 2 × 4.975979 × m
diameter = 9.951 × m
Answer:
Explanation:
<u>Given:</u>
Frequency = f = 40 Hz
<u>Required:</u>
Time period = T = ?
<u>Formula:</u>
<u>Solution:</u>
T = 1 / 40
T = 0.025 seconds
Hope this helped!
<h3>~AH1807</h3>