Answer:
a.
b.
Explanation:
We are given that
a.We have to find the angle
b. We have to find the speed
According to law of conservation of momentum
A block slides along a frictionless surface and onto a slab with a rough surface. The slab has mass of 4 kg and the block has ma
1 answer:
Answer: the friction force on the small block at t equals 1 second is 2N
Explanation:
Given the data in the question;
from the slope in the graph provided, we will get the acceleration of the slab
At t = 1 seconds
Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²
Force = ma = 4 × 0.5 = 2 N
so by Newton's third law
Force on block will be same which is 2N
Therefore the friction force on the small block at t equals 1 second is 2N
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Answer:
<em>The velocity of the carts after the event is 1 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
In a system of two masses, the equation simplifies to:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
The m1=2 kg cart is moving to the right at v1=5 m/s. It collides with an m2= 8 kg cart at rest (v2=0). Knowing they stick together after the collision, the common speed is:
The velocity of the carts after the event is 1 m/s