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Oxana [17]
3 years ago
12

There is a force which resists changes in motion, called

Physics
1 answer:
adoni [48]3 years ago
5 0

Answer:

inertia 11

Explanation:

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Answer: biotic

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Condensation is the process of ____________________.
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D. I hope my answer helps you!
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3 years ago
If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?
Ksju [112]

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

<h3>How to calculate the final velocity a moving object?</h3>

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

  • Initial velocity u = 6m/s
  • Acceleration a = 85m/s²
  • Elapsed time t = 5s
  • Final velocity v = ?

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

Learn more about the first equation of equation here: brainly.com/question/20381052

#SPJ1

7 0
1 year ago
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 47.0° angle from the horizontal.
MariettaO [177]

Answer:

18.7 m

Explanation:

v_{o} = initial speed of the shot = 13 m/s

θ = angle of launch from the horizontal = 47 deg

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 13 Sin47 = 9.5 m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 1.80 m

t = time of travel

Using the kinematics equation

y=v_{oy} t+(0.5)a_{y} t^{2}

- 1.80 = (9.5) t + (0.5) (- 9.8) t²

t = 2.11 s

Consider the motion along the horizontal direction

x = horizontal displacement of the shot

v_{ox} = initial velocity along horizontal direction = 13 Cos47 = 8.87 m/s

a_{x} = acceleration along the horizontal direction = 0 m/s²

t = time of travel =  2.11 s

Using the kinematics equation

x=v_{ox} t+(0.5)a_{x} t^{2}

x = (8.87) (2.11) + (0.5) (0) (2.11)²

x = 18.7 m

8 0
3 years ago
An object moves from point A to point C along the rectangle shown in the figure below.
Naily [24]

Answer:

Hello friend where is the figure of the question

4 0
3 years ago
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