'A' and 'C' both show that behavior.
'D' also shows it, but the object is moving backwards when time begins.
First it moves faster and faster backwards, then it moves slower and slower backwards.
The second law states that the total entropy can never decrese over time for an isolated system
For a constant-velocity object, the average and instantaneous are the same. So the answer is no. It's like taking a running average of a string of numbers that are all the same number. The average is always the sum of the numbers divided by how many have accumulated, which will always equate to the repeated number.
Answer:
a= 0.5m/s^2
Explanation:
Force applied on an object is known as
F=m.a (Newton's second law states it)
a=F/m
a=5/10=0.5m/s^2
