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Crank
3 years ago
15

Given the sequence 31,24,17,10......

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

-39

Step-by-step explanation:

This sequence follows the pattern of subtracting 7 each time. We can prove this:

31 - 7 = 24, 24 - 7 = 17, 17 - 7 = 10

So if we were to continue to the 11th term, we would subtract 7 more times.

1. 10 - 7 = 3

2. 3 - 7 = -4

3. -4 - 7 = -11

4. -11 - 7 = -18

5. -18 - 7 = -25

6. -25 - 7 = -32

7. -32 - 7 = -39

The 11th term in the sequence would be -39.

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A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.
kenny6666 [7]

Answer:

p:y = 3x-10

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

y - y_1 = m(x - x_1)

The point intercept form of line can be written as:

y = mx + c

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10

which is the required slope intercept equation of line p.

4 0
3 years ago
4n-12=12-4n(If there is no solution, type in "no solution") n= Answer
Kipish [7]

Answer:

n = 3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The perimeter of the base of a regular quadrilateral prism is 32 cm. The height of the prism is 2 times greater than the length
horsena [70]

A regular  quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.

Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges  with measure 16 cm is 4.

Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.

7 0
3 years ago
Work out m and c for the line:<br> y=4 - X
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\

Step-by-step explanation:

3 0
3 years ago
Suppose that circles R and S have a central angle measuring 80°. Additionally, circle R has a radius of 3 ft and the radius of c
DerKrebs [107]

Let 

rA--------> radius of the circle R

rB-------> radius of the circle S

SA------> the area of the sector for circle R

SB------> the area of the sector for circle S

 

we have that

rA=3 ft

rB=6 ft

rA/rB=3/6----> 1/2-----------> rB/rA=2

SA=2π ft²

 

we know that

 

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

 

(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(2) ^2*(2π)--->

SB----------- > 8π ft²


the answer is

the area of the sector for circle S is 8π ft²


8 0
3 years ago
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