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2 years ago

How are interference patterns made?

1 answer:

3 0

To set up a stable and clear interference pattern, two conditions must be met: The sources of the waves must be coherent, which means they emit identical waves with a constant phase difference.

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What are two important uses of petroleum

Delvig [45]

Some are fuel,chemicals,plastics,asphalt,and road oil.

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2 years ago

Read 2 more answers

Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m

Ket [755]

Answer:

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

Explanation:

Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

$V_{escape}=\sqrt{\frac{2GM}{R}}$

$V_{escape}=$ Escape velocity

G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²

M= mass of Mars = 6.42×10²³ kg

R = Radius of the Mars = 3.40×10³m

The escape velocity does not depend on the velocity of a object.

$V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}$

$=15.88 \times 10^4$ m/s

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

3 0

2 years ago

Two equally charged, 2.098 g spheres are placed with 3.338 cm between their centers. When released, each begins to accelerate at

photoshop1234 [79]

Answer:

$2.64\times 10^{-7} C$

Explanation:

There are two spheres name 1 and 2 and they posses the same charge, which is +q.

And they have equal mass which is 2.098 g.

The distance between these two spheres is, $r=3.338 cm$ .

And the acceleration of each sphere is, $a=269.429 m/s^{2}$ .

Now the coulumbian force experience by 1 sphere due to 2 sphere,

$F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2} }$ .

And also the newton force will occur due to this force,

$F_{21}=ma$ .

Now equate the above two values of force will get,

$\frac{q^{2} }{4\pi\epsilon_{0} r^{2} } =ma$

Further solve this,

$q^{2}=ma4\pi \epsilon_{0} r^{2}$ .

Substitute all the known variables in above equation,

$q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2})$ .

$q=2.64\times 10^{-7} C$ .

6 0

3 years ago

A tire hanging from a tree is at rest. The force of gravity is pulling down on the tire. Another force, called tension, is pulli

Anton [14]

Answer:

body will stop moving if the gravity will be equal to the tension produced in the string so both the forces will cancel the influence of each other leading to the state when the body is in equilibrium

8 0

2 years ago

How to Answer questions 12 and 13

zubka84 [21]

12) The weight of the plane is $7.35\cdot 10^5 N$

13) The lift provided by the wing is $7.35\cdot 10^5 N$

Explanation:

12)

The weight of an object is equal to the force of gravity acting on the object. Near the Earth's surface, it can be calculated as

$W=mg$

where

W is the weight

m is the mass of the object

g is the acceleration of gravity

In this problem, we know that the mass of the plane is

m = 75 tonnes

Since 1 ton = 1000 kg, the mass in kg is

m = 75,000 kg

Also, the acceleration of gravity is

$g=9.8 m/s^2$

Therefore, the weight of the plane is:

$W=(75,000)(9.8)=7.35\cdot 10^5 N$

13)

We can solve this question by applying Newton's second law along the vertical direction of motion. In fact, the net force acting along the vertical direction must be equal to the product between the mass of the plane and the vertical acceleration:

$\sum F_y = ma_y$