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2 years ago

Write the equation of the circle with center of 10-2 and a radius of 7

Mathematics

1 answer:

True [87]2 years ago

6 0

Answer:

(x-10)^2 + (y-2)^2 = 49

Step-by-step explanation:

I'm assuming that 10-2 means (10,2)

Equation of circle:

(x-a)^2 + (y-b)^2 = r^2

Plugging in the values that we know:

(x-10)^2 + (y-2)^2 = 7^2

(x-10)^2 + (y-2)^2 = 49

Hope this helps!

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Solve by elimination 3×+11y=4,-2×-6y=0

gizmo_the_mogwai [7]

3x + 11y = 4

2x + 6y = 0

I got
15/2, -5/4

6 0

2 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

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2 years ago

Pls help branliest if right

Bezzdna [24]

Answer:

sorry I donot know

I wish I could help

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2 years ago

Which property is demonstrated below? n•1=n

Vinvika [58]

Answer:

Step-by-step explanation:

That'd be the Identity Property of Multiplication.

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2 years ago

11z > -33 help please

stich3 [128]

11z > -33

11z / 11 > 33 / 11

z > 3

Hope it helps!

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2 years ago