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3 years ago

Write the equation of the circle with center of 10-2 and a radius of 7

Mathematics

1 answer:

True [87]3 years ago

6 0

Answer:

(x-10)^2 + (y-2)^2 = 49

Step-by-step explanation:

I'm assuming that 10-2 means (10,2)

Equation of circle:

(x-a)^2 + (y-b)^2 = r^2

Plugging in the values that we know:

(x-10)^2 + (y-2)^2 = 7^2

(x-10)^2 + (y-2)^2 = 49

Hope this helps!

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3 years ago

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Answer:

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algol [13]

Because Q and R are independent, you have

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3 years ago

93. Let f(x) = 3x - 1 and g(x) = x + 5. Evaluate the following limits. (a) lim x→3 f(g(x)] (b) lim x→3 g[f(x)]

Ipatiy [6.2K]

Answer:

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Step-by-step explanation:

steps are in picture.

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3 years ago

Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r

Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>

Since the degree of given polynomial is 4
Therefore it must have four roots.
Already given that the given polynomial has 1 positive real root and 1 negative real root .
Every polynomial with degree greater than 1 has atleast one imaginary root.

<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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3 years ago