Answer:
8/15
Step-by-step explanation:
Given the equation representing the pathway of sam's dive into the swimming pool, his height after two seconds is -22ft.
<h3>What is a Quadratic Equation?</h3>
Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is;
ax² + bx + c = 0
Where x is the unknown
Given the data in the question
- Equation of the pathway of sams dive into the swimming pool is h = -16t² + 15t + 12.
- Time t = 2.0 seconds
- Height h = ?
Now, to get the height after 2 seconds, we substitute 2 for t in the equation.
h = -16t² + 15t + 12.
If t = 2
h = -16(2)² + 15(2) + 12
h = -16(4) + 30 + 12
h = -64 + 30 + 12
h = -64 + 42
h = -22ft
Therefore, given the equation representing the pathway of sam's dive into the swimming pool, his height after two seconds is -22ft.
Learn more about quadratic equations here: brainly.com/question/1863222
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Answer:
y=10
Step-by-step explanation:
3y-8=22
-8 -8
3y=30
divide both sides by 3
y=10
Answer:
W = 69.5 L = 109.5
Step-by-step explanation:
L = 3W-99
Perimeter = 2L + 2W
358 = 2(3W-99) + 2W
358 = 6W-198 + 2W
358 = 8W-198
556 = 8W
69.5 = W
- 358 = 2L+2W
- 358 = 2L + 2(69.5)
- 358 = 2L + 139
- 219 = 2L
- L = 109.5