Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
In the RGB (Red, Green, Blue) color model, the numbers 0-255 represent the intensities of each color beam
.Each number represents an intensity value is on a scale of 0 to 255, It can be also written in hexadecimal form, from 00 to FF.
RGB values are encoded as 8-bit integers, which range from 0 to 255.
Answer:
The advantage for the above condition is as follows:-
Explanation:
- If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
- It is because when there is a needs to change the value of that variable, then it can be done when the user changes the value in one place. There is no needs to change the vale in multiple places.
- But if there is a value in multiple places instead of a variable and there is no constant variable, then the user needs to change the value in multiple places.
Explanation:
<h2>
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<em><u>Edge computing with 5G creates tremendous opportunities in every industry. It brings computation and data storage closer to where data is generated, enabling better data control, reduced costs, faster insights and actions, and continuous operations. In fact, by 2025, 75% of enterprise data will be processed at the edge, compared to only 10% today.¹IBM provides an autonomous management offering that addresses the scale, variability and rate of change in edge environments. IBM also offers solutions to help communications companies modernize their networks and deliver new services at the edge.</u></em></h2>
Hope this answer is helpful
The answers are 3,5, and 6
