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makkiz [27]
3 years ago
9

The heat of a reaction may be found with the equation q=mcΔT. A hot pot is set on a 2.51 kg slab of granite. The temperature of

the granite increases from room temperature, 23.5°C, to 98.6°C. Calculate the heat absorbed by the granite given that the specific heat capacity of granite is 0.79 J/(g*°C). A) 47 kJ B) 129 kJ C) 149 kJ D) 196 kJ
Chemistry
2 answers:
ahrayia [7]3 years ago
6 0

The answer is C) 149 kJ

bagirrra123 [75]3 years ago
3 0
I believe the answer to that is c!!!
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If I have 2.4g of magnesium, how many g of oxygen(O2 ) will I need to react completely with the magnesium? 2Mg +O2 → MgO
Jet001 [13]

Explanation:

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5 0
3 years ago
How many significant digits are 6.3590x10 7 mm
Svet_ta [14]
If you go by the decimal there should be 5 significant digits because 0 is a trailing zero and matters since it comes after a decimal. however if you do 

6.3590 x 10 ^7 = 63590000 then you would only have 4 significant digits because there is no longer a decimal to make the zero after the 9, significant. 

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8 0
2 years ago
Read 2 more answers
The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a
DIA [1.3K]

Answer:

Empirical formula = C5H4

Molecular formula = C10H8

Explanation:

When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

We calculate the molar composition of the sample. We look for the molecular weights in the periodic table:

CO2 = 12,011 + 2 (15,999) = 44,009 g

Mol C = 10.3 mg * (1 mol CO2 / 44.009 g CO2) * (1 mol C / 1 mol CO2) = 0.234 mmol C

Mass C = 0.234 mmol C * (12.011 g C / 1 mol C) = 2.8105 mg C

Mass H = 3 mg - 2.8105 mg = 0.1895 mg H

Mol H = 0.1895 mg H * (1 mol H / 1,008 g H) = 0.188 mmol H

To calculate the empirical formula, we must divide the number of moles of each element by the smallest number of moles, in this case, of hydrogen:

C = 0.2340 mmol C / 0.1895 mol H = 1.25

H = 0.1895 mmol H / 0.1895 mmol H = 1

We multiply the coefficients by 4, and we have the empirical formula:

C1.25 * 4H1 * 4 = C5H4

The molecular formula is equal to (C5H4)m, where m is calculated by the molecular and empirical mass ratio, as follows:

Empirical mass = (5 * 12.011) + (4 * 1.008) = 64.09 g

m = 130 g / 64.09 g = 2.02 = 2

Therefore we have the molecular formula:

(C5H4)2 = C10H8

4 0
3 years ago
Explain why 5.00 grams of salt does not contain the same number of particles as 5.0 grams of sugar​
Tom [10]

Answer:

5.00 grams of salt contain more particles than 5.0 grams of sugar​

Explanation:

Salt = NaCl

Molar mass = 58.45  g/mol

Sugar = C₁₂H₂₂O₁₁

Molar mass = 342.3 g/mol

Sugar's molar mass is higher than salt.

So 1 mol of sugar weighs more than 1 mol of salt

But 5 grams of salt occupies more mole than 5 grams of sugar

5 grams of salt = 5g / 58.45 g/m = 0.085 moles

5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles

In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.

3 0
3 years ago
Calculate the value deltaG°​
atroni [7]

Answer:

ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.

Explanation:

4 0
3 years ago
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