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3 years ago

How many liters of a 1.5 M solution can you make if you have .50 mol of KCl?

Chemistry

1 answer:

vaieri [72.5K]3 years ago

7 0

Answer:

The answer to your question is 0.33 liters

Explanation:

Data

Volume = ?

Molarity = 1.5 M

number of moles = 0.5

Formula

$Molarity = \frac{number of moles }{volume}$

Solve for V

$Volume = \frac{number of moles}{molarity}$

Substitution

$Volume = \frac{0.5}{1.5}$

Simplification and result

Volume = 0.33 l

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The number of moles of solute in 200.ml of a 0.500 m solution is

IrinaK [193]

Answer:

I believe the answer is 0.100.

Explanation:

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3 years ago

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2 years ago

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2 years ago

Read 2 more answers

(Help would be greatly appreciated) What is the molarity of a solution made from 325.4g of AlCl3 with enough water to make 500.0

puteri [66]

Answer:

4.88 M

Explanation:

M = number moles/Volume (L)

MM AlCl3 = 133.34 g/mol

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7 0

2 years ago

What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2<br> ? ...?

elena-s [515]

To make a first step you have to know the balanced form for neutralization formula: $Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)
$
According to this, you can <span>calculate what you are being asked :</span> $0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl$
Then we have : $0.140MHCl=0.140(mol/L)HCl$
Hope everything is clear, here is the exact answer you need : $V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl
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8 0

2 years ago