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Roman55 [17]
2 years ago
14

Two spheres of equal mass, A and B, are projected off the edge of a 1.0 m bench.    Sphere A has a horizontal velocity of 10 m/s

and sphere B has a horizontal velocity of 5 m/s.
__ 5.    If both spheres leave the edge of the table at the same instant, sphere A will land
a.    at some time after sphere B.
b.    at the same time as sphere B.
c.    at some time before sphere B.
d.    There is not enough information to decide.

__ 6.    If both spheres leave the edge of the table at the same instant, sphere A hits the floor at the spot marked X.  Sphere B will hit the floor
a.    at some point between the edge of the table and X.
b.    at some point past X.
c.    at the same distance from the table as X.
d.    there is not enough information to decide.
​
Physics
1 answer:
suter [353]2 years ago
4 0

Answer:

c. because A will land first becuase its heavier

and D.

Explanation:

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7 0
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Which object has the least momentum? object a: m = 1 kg, v = 100 m/s object b: m = 10 kg, v = 12 m/s object c: m = 0.5 kg, v = 1
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b = 10 * 12 = 120 Ns
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8 0
3 years ago
3x/y=6g/b solve for x
lora16 [44]
So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1)  3x    6g
     ---- = ---
     y       b

2)  3xb    6gy
     ------ = -----   
     yb       yb

3)       3xb    6gy
  (yb) ------ = -----  
          yb       yb
which becomes: 3xb = 6gy

So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).

3xb   6gy
----- = -----
3b      3b

where you will then find your answer of:
      2gy
x = -----       (simplified by the GCM of 3)
       b
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