Answer:
Explanation:
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Answer:
h’ = 1/9 h
Explanation:
This exercise must be solved in parts:
* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy
starting point. Higher
Em₀ = U = m g h
final point. Lower, just before the crash
Em_f = K = ½ m
energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v_b =
* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved
initial instant. Just before the crash
p₀ = 2m 0 + m v_b
final instant. Right after the crash
p_f = (2m + m) v
the moment is preserved
p₀ = p_f
m v_b = 3m v
v = v_b / 3
v = ⅓ 
* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together
Starting point. Lower
Em₀ = K = ½ 3m v²
Final point. Higher
Em_f = U = (3m) g h'
Em₀ = Em_f
½ 3m v² = 3m g h’
we substitute
h’=
h’ =
h’ = 1/9 h
Explanation:
Bulbs are nothing but resistors that glow when current passes through them.
In Set A, the bulbs (resistors) are connected parallely to each other, this means that even if one of the bulbs fuses or removed, the circuit will still be completed and others continue to glow.
And in parallel connection if the resistance of the two resistors are same powered delivered to each is same.
In Set B, bulbs are in series connection, this means that when one of the bulb is removed or fuses, the circuit will break and other bulbs can not operate.In this situation as well if the resistance of two resistors is same then the power delivered is same.
Answer:
(a) 
(b) 
Explanation:
Given data

Solution
For Part (a)
As the velocity component in direction of y is given by:

The maximum displacement is given by:

For Part (b)
To reach y=46cm =0.46m apply:
