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3 years ago

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A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I

f an object is placed 40 cm to the left of the converging lens, the total magnification is: Group of answer choices –1.0 –3.0 +2.0 –1.5 +3.0

1 answer:

scZoUnD [109]3 years ago

3 0

Answer:

Magnification will be equal to 3

Explanation:

We have given focal length of the converging lens $F_1=20cm$

Focal length of the diverging lens $F_2=30cm$

Object is placed 40 cm to the length of the converging lens d = 40 cm

Combination of the focal length will be equal to

$\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}$

$\frac{1}{F}=\frac{1}{20}+\frac{1}{-30}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}$

F = 60 cm

So combination of the focal length will be 60 cm

Magnification is given by

$M=\frac{F}{F-d}=\frac{60}{60-40}=3$

So magnification will be equal to 3

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Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti

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Answer:

A) The speed of the water must be 8.30 m/s.

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Explanation:

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Velocity achieved by squid = $v_1=2.60 m/s$

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Velocity by which water was released by squid = $v_2$

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P = P'

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Kinetic energy of water = K.E' = $\frac{1}{2}m_2v_2^{2}$

Total kinetic energy created by this maneuver:

$K.E+K.E'=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}$

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3 years ago

Vector vector a has a magnitude of 29 units and points in the positive y-direction. when vector vector b is added to vector a ,

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Good morning.

We have:

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We add the vector -a to both sides:

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Therefore, the magnitude of b is 47 units.

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