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3 years ago

How many inner shell electrons are there in Bohr model

Physics

1 answer:

Paha777 [63]3 years ago

4 0

Answer:

10 is the correct answer

Explanation:

It is ten because the electrons that encircled the two orbit before the third orbit if the bohr model is 10. In bohr model, the electrons encircled the nucleus of an atom called orbit.

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A particle initially located at the origin has an acceleration of = 2.00ĵ m/s2 and an initial velocity of i = 8.00î m/s. Find (a

sergejj [24]

a. The particle has position vector

$\vec r(t)=\left(\left(8.00\dfrac{\rm m}{\rm s}\right)t\right)\,\vec\imath+\left(\dfrac12\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\right)\,\vec\jmath$

$\vec r(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)t\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath$

b. Its velocity vector is equal to the derivative of its position vector:

$\vec v(t)=\vec r'(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath$

c. At $t=7.00\,\mathrm s$ , the particle has position

$\vec r(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)(7.00\,\mathrm s)\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)^2\,\vec\jmath$

$\vec r(7.00\,\mathrm s)=\left(56.0\,\vec\imath+49.0\,\vec\jmath\right)\,\mathrm m$

That is, it's 56.0 m to the right and 49.0 m up relative to the origin, a total distance of $\|\vec r(7.00\,\mathrm s)\|=\sqrt{(56.0\,\mathrm m)^2+(49.0\,\mathrm m)^2}=74.4\,\mathrm m$ away from the origin in a direction of $\theta=\tan^{-1}\dfrac{49.0\,\mathrm m}{56.0\,\mathrm m}=41.2^\circ$ relative to the positive $x$ axis.

d. The speed of the particle at $t=7.00\,\mathrm s$ is the magnitude of the velocity at this time:

$\vec v(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)\,\vec\jmath$

$\vec v(7.00\,\mathrm s)=\left(8.00\,\vec\imath+14.0\,\vec\jmath\right)\dfrac{\rm m}{\rm s}$

Then its speed at this time is

$\|\vec v(7.00\,\mathrm s)\|=\sqrt{\left(8.00\dfrac{\rm m}{\rm s}\right)^2+(14.0\dfrac{\rm m}{\rm s}\right)^2}=16.1\dfrac{\rm m}{\rm s}$

4 0

3 years ago

A sound wave with a power of 8.8 × 10–4 W leaves a speaker and passes through section A, which has an area of 5.0 m2. What is th

statuscvo [17]

The intensity of the sound wave is defined as the ratio between the power of the wave and the area through which the wave passes:
$I= \frac{P}{A}$
where
I is the intensity
P is the power
A is the area

If we use the data of the problem, $P=8.8 \cdot 10^{-4}W$ and $A=5.0 m^2$ , we find the intensity of the sound wave:
$I= \frac{P}{A}= \frac{8.8 \cdot 10^{-4} W}{5.0 m^2}=1.76 \cdot 10^{-4} W/m^2$

6 0

3 years ago

"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66

Kamila [148]

Answer:

56°

Explanation:

Brewsters angle can be simply derived from

n1sin theta1= n2sintheta2= n2costheta1

because the reflected light will be 100% polarized if it is reflected at an angle 90o to the refracted light. Hence, Brewsters angle is

Tan theta= n2/n1

1.66/1.11= 1.495

Theta = 56°

Explanation:

7 0

4 years ago

A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds

vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

$\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s$

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s x 29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

8 0

3 years ago

Distinguish between the key features of Charles's Law and

Alborosie

Answer:

The answer is below

Explanation:

Charles law states that the volume and temperature of a fixed amount of a gas is directly proportional to each other provided that pressure is held constant.

Boyle's law states that the volume and pressure of a fixed amount of a gas are inversely proportional to each other provided that temperature is held constant.

a) Constant property:

In Charles law, pressure is kept constant while in Boyle's law, temperature is held constant.

b) Varying properties:

In Charles law, volume and temperature are varying while in Boyle's law, pressure and volume are varying.

c) Type of variance:

In Charles law we have a direct variance while in Boyle's law we have an indirect variance.

d) Charles law is given as:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Boyle's law is given as:

$P_1V_1=P_2V_2$

7 0

3 years ago