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marishachu [46]
3 years ago
15

How many formula units are in 25.4 g of MgCl2?

Chemistry
1 answer:
stiv31 [10]3 years ago
5 0

Answer: 1.58 x 10^{23}

Explanation:

1 mole of magnesium chloride has a mass of 95.211 g and contains 6.022⋅10^{23}formula units of magnesium chloride, you can say that,

25.0 g x (6.022 x 10^{23} form units MgCl2) /95.211 = 1.58 x 10^{23}

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Two liquids, a and b are immiscible. liquid a has a density of 0.89 g/ml. liquid b has a density of 0.72 g/ml. what would you ex
Burka [1]
In the given above, we have two densities which are 0.89 g/mL and 0.72 g/mL. We are also given that the liquids are immiscible. After the settlement of the liquids, they will form two layers.

The heavier substance, the one which has a higher density will be at the bottom and the lighter substance, the one which has a lower density will be at the top layer.
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4 years ago
When elemental boron, B, is burned in oxygen gas, the product is diboron trioxide. If the diboron trioxide is then reacted with
zalisa [80]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

The chemical equation for the reaction of elemental boron and oxygen gas follows:

4B+3O_2\rightarrow 2B_2O_3

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

B_2O_3+3H_2O\rightarrow 2H_3BO_3

By Stoichiometry of the reaction:

1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.

Hence, the chemical equations are written above.

3 0
3 years ago
How many of the zeros in the measurement 0.050060 are significant
Feliz [49]
I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore
6 0
3 years ago
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A. Use the following steps to balance the redox reaction below. Al(s) Ni2 (aq) Ni(s) Al3 (aq)
Alja [10]

Answer:

2Al(s) +3Ni²⁺(aq) ⟶ 2Al³⁺(aq) + 3Ni(s)  

Explanation:

The unbalanced equation is

Al(s) + Ni²⁺(aq) ⟶ Ni(s) + Al³⁺(aq)

(i) Half-reactions

Al(s) ⟶ Al³⁺(aq) + 3e⁻

Ni²⁺(aq) + 2e⁻ ⟶ Ni(s)

(ii) Balance charges

2 × [Al(s) ⟶ Al³⁺(aq) + 3e⁻]

3 × [Ni²⁺(aq) + 2e⁻ ⟶ Ni(s)]

gives

2Al(s) ⟶ 2Al³⁺(aq) + 6e⁻

3Ni²⁺(aq) + 6e⁻ ⟶ 3Ni(s)

(iii) Add equations

2Al(s) ⟶ 2Al³⁺(aq) + 6e⁻

<u>3Ni²⁺(aq) + 6e⁻ ⟶ 3Ni(s)                                       </u>  

2Al(s) +3Ni²⁺(aq) + <em>6e</em>⁻ ⟶ 2Al³⁺(aq) + 3Ni(s) + <em>6e⁻ </em>

Simplify (cancel electrons)

2Al(s) +3Ni²⁺(aq) ⟶ 2Al³⁺(aq) + 3Ni(s)

8 0
3 years ago
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