Answer:
The expected number of days per week the captain can leave port is 4.05.
Step-by-step explanation:
We are given the following distribution:
![P(X = 0) = 0.2](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%200.2)
![P(X = 1) = 0.05](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%200.05)
![P(X = 2) = 0.05](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%200.05)
![P(X = 3) = 0.05](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%200.05)
![P(X = 4) = 0.15](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%200.15)
![P(X = 5) = 0.1](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%200.1)
![P(X = 6) = 0.15](https://tex.z-dn.net/?f=P%28X%20%3D%206%29%20%3D%200.15)
![P(X = 7) = 0.25](https://tex.z-dn.net/?f=P%28X%20%3D%207%29%20%3D%200.25)
What is the expected number of days per week the captain can leave port.
We multiply each outcome by its probability. So
![E = 0*0.2 + 1*0.05 + 2*0.05 + 3*0.05 + 4*0.15 + 5*0.1 + 6*0.15 + 7*0.25 = 4.05](https://tex.z-dn.net/?f=E%20%3D%200%2A0.2%20%2B%201%2A0.05%20%2B%202%2A0.05%20%2B%203%2A0.05%20%2B%204%2A0.15%20%2B%205%2A0.1%20%2B%206%2A0.15%20%2B%207%2A0.25%20%3D%204.05)
The expected number of days per week the captain can leave port is 4.05.
Tom has to grow 20% in order to become 48 inches tall.
Answer:
32
Step-by-step explanation:
4(5+3)=
20+12=
32
or
4(5+3)=
4(8)=
32
Answer:
6 choose 3 = 20
Step-by-step explanation:
![=\frac{n!}{r!\left(n-r\right)!}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bn%21%7D%7Br%21%5Cleft%28n-r%5Cright%29%21%7D)
6 choose 3 = 20