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beks73 [17]
3 years ago
10

If BCD ~ GEF, find BD​

Mathematics
2 answers:
Kruka [31]3 years ago
5 0

Answer:

la esquina prestado y si no entiende pregúntale al profe

Masja [62]3 years ago
4 0

Answer:

19

Step-by-step explanation:

if the triangles are similar then EG/BC = FG/BD

51/(x+4) = 57/(2x-7) cross multiply expressions

102x - 357 = 57x + 228

102x - 57x = 228 + 357

45x = 585 divide both sides by 45

x = 13

BD = 2x -7 and 13×2 - 7 = 19

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In the ordered pair (2, 3), what is the x-coordinate? y-coordinate?
blagie [28]

Answer:

2 = x- coordinate

3 = y coordinate

Step-by-step explanation:

REMEMBER: In an ordered pair, the x-coordinate always comes first.

3 0
3 years ago
35 points!! Only comment if you really know the answer please.
hodyreva [135]
Y = 3x - 1 ---- (1)
x - y = -9  ---- (2)

From Equation 2:
x - y = - 9
x + 9 = y 
y = x + 9 --- (2a)

(1) - (2a):
0 = 3x - x - 1 - 9
0 = 2x - 10
2x - 10 = 0
2x = 10
x = 5 ---- sub into (1)

y = 3(5) - 1 
y = 15 - 1
y = 14 

5 0
3 years ago
Heart failure is due to either natural occurrences (89%) or outside factors (11%). Outside factors are related to induced substa
Firdavs [7]

Answer:

a) 11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

b) 0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

c) The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

Step-by-step explanation:

We have these following probabilities:

89% probability that a patient has heart failure due to natural occurrences.

11% probability that a patient has heart failure due to outside factors.

A) What is the probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors?

We assume that causes of heart failure between individuals are independent, which means that the probabilities are the same for each patient. So:

11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

B) What is the probability that third patient with heart failure that enters the emergency room is the first one due to outside factors?

First two due to natural occurrences, each with 89% = 0.89 probability.

Third due to outside factors, with 11% = 0.11 probability. So

0.89*0.89*0.11 = 0.0871

0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

C) What is the mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors?

11% with outside factors, so the mean number of patients before the first with outside factors is given by

m = 1/0.11 = 9.09

The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

4 0
3 years ago
1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera
Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}

SP \approx 8.246

PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}

PA \approx  8.246

AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}

AZ \approx 8.246

ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}

ZS \approx 8.246

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

m_{SA} = \frac{6-(-4)}{6-(-4)}

m_{SA} = 1

m_{PZ} = \frac{4-(-2)}{-2-4}

m_{PZ} = -1

Since m_{SA}\cdot m_{PZ} = -1, diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)

M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)

M_{SA} = (-2,-2)+(3,3)

M_{SA} = (1,1)

M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)

M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)

M_{PZ} = (2,-1)+(-1,2)

M_{PZ} = (1,1)

Then, the diagonals SA and PZ bisect each other.

8 0
2 years ago
Solve for b. -1/6b=3
zhannawk [14.2K]

Answer:

b = -18

Step-by-step explanation:

-1/6b=3

Multiply each side by -6

-6*-1/6b=3(-6)

b = -18

3 0
3 years ago
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