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melamori03 [73]
3 years ago
13

Describe how noise-cancelling headphones modify the sound waves around the user. Your answer should be three to four sentences i

n length and contain proper grammar and punctuation.
Physics
1 answer:
amm18123 years ago
3 0
<h3><u><em>Answer: Describe how noise-cancelling headphones modify the sound waves around the user. Your answer should be three to four sentences in length and contain proper grammar and punctuation?  How Noise-canceling Headphones Work </em></u></h3><h3><u><em> </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Noise-canceling Headphones </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Bose was the first company to introduce noise-canceling headphones. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Bose was the first company to introduce noise-canceling headphones. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>PHOTO COURTESY CONSUMER PRODUCTS </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Unfortunately for music lovers, many types of ambient sounds can interfere with or even block the sounds coming through their headphones. If you have ever tried to listen to a CD or MP3 player on a plane, then you know the problem well: The roar of the engines makes it difficult to hear what's being piped through the speakers -- even when those speakers are situated in or on your ear. Fortunately, noise-canceling headphones can provide a more enjoyable listening experience. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Noise-canceling headphones come in either active or passive types. Technically speaking, any type of headphones can provide some passive noise reduction. That's because the materials of the headphones themselves block out some sound waves, especially those at higher frequencies. The best passive noise-canceling headphones, however, are circum-aural types that are specially constructed to maximize noise-filtering properties. That means they are packed with layers of high-density foam or other sound-absorbing material, which makes them heavier than normal headphones. The tradeoff of all that extra weight is a reduction in noise of about 15 to 20 decibels (dB). But considering jet engines create 75 to 80 dB of noise inside the aircraft cabin, passive models have some serious limitations. That's where active noise-canceling headphones come in. </em></u></h3><h2><u><em> </em></u></h2>

<u><em></em></u>

<h2><u><em>Hope this Helps you!! Good Luck with your Quiz/Assignment/Test!! Don't forget to mark as Brainliest!! :)</em></u></h2>

<u><em /></u>

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A bullet of mass 6.20 10-3 kg, moving at 1320 m/s impacts a tree stump and penetrates 11.00 cm into the wood before coming to re
sladkih [1.3K]

Answer:

  F = -49.1   10³ N

Explanation:

Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant

   v_{f}² = v₀² + 2 a x

Since the bullet is at rest, the final speed is zero

    x = 11.00 cm (1 m / 100 cm) = 0.110 m

    0 = v₀² + 2 a x

   a = -v₀² / 2 x

   a = -1320²/(2 0.110)

   a = -7.92 10⁶ m / s²

With Newton's second law we find the force

   F = m a

   F = 6.20 10⁻³ (-7.92 10⁶)

   F = -49.1   10³ N

The sign means that it is the force that the tree exerts to stop the   bullet

8 0
3 years ago
When discussing Newton's laws of motion,which terms do people most likely yse when talking about Newton's third law of motion?​
mestny [16]

When discussing Newton's laws of motion, particularly Newton's third law of motion, the terms that almost everyone will use are "action"​ and "reaction".

You must not take this to mean that they understand what they're talking about.

4 0
3 years ago
Oil _____.
atroni [7]
Oil <span>must be mined from underground 

Oil is NOT a renewable resource
Oil does NOT release more toxins than coal
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4 0
3 years ago
Read 2 more answers
Can some answer 7 a and b please
pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

V_{f} =1.7 m/s

Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

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3 years ago
Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up
kirza4 [7]

Answer:

I believe the answer is b

Explanation:

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