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melamori03 [73]
3 years ago
13

Describe how noise-cancelling headphones modify the sound waves around the user. Your answer should be three to four sentences i

n length and contain proper grammar and punctuation.
Physics
1 answer:
amm18123 years ago
3 0
<h3><u><em>Answer: Describe how noise-cancelling headphones modify the sound waves around the user. Your answer should be three to four sentences in length and contain proper grammar and punctuation?  How Noise-canceling Headphones Work </em></u></h3><h3><u><em> </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Noise-canceling Headphones </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Bose was the first company to introduce noise-canceling headphones. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Bose was the first company to introduce noise-canceling headphones. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>PHOTO COURTESY CONSUMER PRODUCTS </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Unfortunately for music lovers, many types of ambient sounds can interfere with or even block the sounds coming through their headphones. If you have ever tried to listen to a CD or MP3 player on a plane, then you know the problem well: The roar of the engines makes it difficult to hear what's being piped through the speakers -- even when those speakers are situated in or on your ear. Fortunately, noise-canceling headphones can provide a more enjoyable listening experience. </em></u></h3><h3><u><em> </em></u></h3><h3><u><em>Noise-canceling headphones come in either active or passive types. Technically speaking, any type of headphones can provide some passive noise reduction. That's because the materials of the headphones themselves block out some sound waves, especially those at higher frequencies. The best passive noise-canceling headphones, however, are circum-aural types that are specially constructed to maximize noise-filtering properties. That means they are packed with layers of high-density foam or other sound-absorbing material, which makes them heavier than normal headphones. The tradeoff of all that extra weight is a reduction in noise of about 15 to 20 decibels (dB). But considering jet engines create 75 to 80 dB of noise inside the aircraft cabin, passive models have some serious limitations. That's where active noise-canceling headphones come in. </em></u></h3><h2><u><em> </em></u></h2>

<u><em></em></u>

<h2><u><em>Hope this Helps you!! Good Luck with your Quiz/Assignment/Test!! Don't forget to mark as Brainliest!! :)</em></u></h2>

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To move the Center of Gravity (CG) forward, you could do which of the following?
Sergio039 [100]

Answer:

I think it's no. 3

Decrease the volume of the horizontal and vertical stabilizer material.

Explanation:

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7 0
3 years ago
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A 25N force is acting on a body moving on a straight line with Initial momentum 20 kam's. Find the final momentum after 4 second
Nezavi [6.7K]

The final momentum of the body is equal to 120 Kg.m/s.

<h3>What is momentum?</h3>

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: {\displaystyle \mathbf {p} =m\mathbf {v} . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

Given the initial momentum of the body = Pi = 20 Kg.m/s

The force acting on the body, Pf = 25 N

The time, Δt = 4-0 = 4s

The Force is equal to the change in momentum: F ×Δt = ΔP

25 × 4 = P - 20

100 = P - 20

P = 100 + 20 = 120  Kg.m/s

Therefore, the final momentum of a body is 120 Kg.m/s.

Learn more about momentum, here:

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5 0
1 year ago
When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for
sveta [45]

Answer:

F = -4567.40 N

Explanation:

Given that,

The power developed by the engine, P = 196 hp

1 hp = 746 W

196 hp = 146157 W

Speed of the car, v = 32 m/s

Let F is the total friction force acting on the car. The product of force and velocity is called the power developed by the engine. It is given by :

P=-F\times v

F=\dfrac{-P}{v}

F=\dfrac{-146157\ W}{32\ m/s}

F = -4567.40 N

So, the total frictional force acting on the car is 4567.40 N. Hence, this is the required solution.

7 0
3 years ago
The components of vector A are Ax = +2.2 and Ay = -6.9 , and the components of vector B are given are Bx = -6.1 and By = -2.2. W
Zina [86]
For simplicity, let's call vector B-A  vector C  Then C is
Cx = (-6.1 - 2.2)  
Cy = (-2.2 - (-6.9))  Or,
Cx = -8.3  Cy = 4.7
The magnitude is found with the Pythagorean theorem
||C|| = √(-8.3² + 4.7²) = 9.538
3 0
3 years ago
How fast much an 816kg Volkswagen travel to have the same momentum as (a) a 2650kg Cadillac going 16.0 km/h? (b) a 9080-kg truck
Katyanochek1 [597]

Answer:

Explanation:

From the given information:

the car's momentum = momentum of the truck

∴

(a) 816 kg × v = 2650 kg × 16.0 km/h

v = (2650 kg × 16.0 km/h) /  816 kg

v = 51.96 km/hr

(b) 816 kg × v = 9080 kg × 16.0 km/h

v = (9080 kg × 16.0 km/h) /  816 kg

v = 178.04 km/hr

8 0
3 years ago
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