Answer:
37.33m
Explanation:
Using the equation of motion
S = ut + 1/2gt^2
Time t = 2.76secs
g = 9.8m/s^2
S = 0 + 1/2(9.8)(2.76)^2
S = 4.9*7.6176
S = 37.33
Hence the window is 37.33m above the ground
They become old and explode.
Answer:
Maximum permitted surface crack length is 1.29 mm
Explanation:
As per the question:
Tensile stress, 
Surface energy of magnesium oxide, SE = 
Modulus of elasticity of the material, E = 225 GPa = 
Now,
To calculate the maximum allowable surface crack length:


Answer:
<h2>D) S increases because at all times Rock X falls with a greater speed than Rock Y</h2>
Explanation:
As we know that Stone X is dropped first and then after some time stone Y is dropped
Now we have

similarly for Y

now the relative acceleration of two stones while they are in air is ZERO
also we know from above equations

so the separation between two stones will keep on increasing as the speed of X is more than the speed of Y